I would say the answer is P2O5. Some teachers use PO2.5. I'm not one of them.
Answer:
- Neutral solutions: concentration of hydronium equals the concentration of hydroxide.
- Acid solutions: concentration of hydronium is greater than the concentration of hydroxide.
- Basic solutions concentration of hydronium is lower than the concentration of hydroxide.
Explanation:
Hello,
It is widely known that the pH of water is 7, therefore the pOH of water is also 7 based on:

In such a way, we can compute the concentration of hydronium and hydroxide ions as shown below:
![pH=-log([H^+])\\](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29%5C%5C)
![[H^+]=10^{-pH}=10^{-7}=1x10^{-7}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-pH%7D%3D10%5E%7B-7%7D%3D1x10%5E%7B-7%7DM)
![pOH=-log([OH^-])](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%29)
![[OH^-]=10^{-pOH}=10^{-7}=1x10^{-7}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-pOH%7D%3D10%5E%7B-7%7D%3D1x10%5E%7B-7%7DM)
Thus, we notice that the relationship between the concentration of the hydronium is equal for water or neutral solutions. Moreover, if we talk about acid solutions, pH<OH therefore the concentration of hydronium is greater than the concentration of hydroxide. On the other hand if we talk about basic solutions, pH>OH therefore the concentration of hydronium is lower than the concentration of hydroxide.
Best regards.
I think Both protons and neutrons (and their anti-particles) froze out at 1013 K, about 0.0001 seconds after the Big Bang. Protons and neutrons are sub atomic particles of an atom that are found in the nucleus of an atom. Proton is the positively charge particle while the neutron has no charge. The proton positive charge accounts for the positive nuclear charge.
Answer:
See below.
Explanation:
The mass of octane in the sample of gasoline is 0.02851 * 482.6 = 13.759 g of octane.
The balanced equation is:
2C8H18(l) + 25O2(g) ----> 16CO2(g) + 18H2O(g)
From the equation, using atomic masses:
228.29 g of octane forms 704 g of CO2 and 324.3 g of H2O
So the mass of CO2 formed from the combustion of 13.759 g of octane = (704 * 13.759) / 228.29
= 42.43 g of CO2.
Amount of water = 324.3 * 13.759) / 228.29
= 19.55 g of H2O.
Answer: The molecular formula is
Explanation:
We are given:
Mass of
= 0.1605 g
Mass of
= 0.0220 g
mass of
= 0.1425 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of H =
Moles of S =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For S =
The ratio of C : H: S= 3: 5: 1
Hence the empirical formula is
The empirical weight of
= 3(12)+5(1)+1(32)= 73g.
The molecular weight = 146 g/mole
Now we have to calculate the molecular formula.
The molecular formula will be=