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Chemistry

2 answers:

vampirchik [111]2 years ago

8 0

Answer:

its b alkyne

Explanation:

brinliest po plsss

jeyben [28]2 years ago

4 0

Answer:

Alkyne so its b

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For the reaction PC15 (8) PC13 (g) + Cl2 (g) K = 0.0454 at 261 °C. If a vessel is filled with these gases such that the initial

Fiesta28 [93]

Answer:

The correct answer is B.

The $K_{eq}$ is samller than $Q$ of the reaction . So,the reaction will shift towards the left i.e. towards the reactant side.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

The expression for $Q$ is written as:

$Q=\frac{[PCl_3][Cl_2]}{[[PCl_5]^1}$

$Q=\frac{0.20 M\times 2.5 M}{0.20 M}$

$Q=2.5$

Given : $K_{eq}$ = 0.0454

Thus as $K_{eq}$ , the reaction will shift towards the left i.e. towards the reactant side.

4 0

3 years ago

Read 2 more answers

Draw the product(s) that are expected when tert-butyl bromide undergoes solvolysis in isopropanol, (CH3)2CHOH.

N76 [4]

Those reactions in which Alkyl Halide reacts with the solvent without the involvement of any acid or base is called as Solvolysis. In given problem <em>tert</em>-Butyl Bromide is a tertiary Alkyl Halide and we know well that tertiary alkyl halides undergo SN¹ and E¹ elimination reaction due to the formation of stable tertiary carbocation. In given example after the formation of carbocation when Isopropyl act as nucleophile it will produce ether and when it acts as a base it will produce unsaturated compound. The reaction along with both products is shown below,