Answer:it all above
Explanation:
it all above because all the answer are truth so it all above
I believe this pertains to chemical reaction? So my guess would be answer A “Fire burning”
Don’t quote me though lol.
Answer:
Pb(s) ---> Pb+2 + 2e- is the anode
Cu+2(aq) + 2e- ---> Cu(s) is the cathode
The combustion reaction of octane is as follow,
C₈H₁₈ + 25/2 O₂ → 8 CO₂ + 9 H₂O
According to balance equation,
8 moles of CO₂ are released when = 114.23 g (1 mole) Octane is reacted
So,
6.20 moles of CO₂ will release when = X g of Octane is reacted
Solving for X,
X = (114.23 g × 6.20 mol) ÷ 8 mol
X = 88.52 g of Octane
Result:
88.52 g of Octane is needed to release 6.20 mol CO₂.
PF3 is phosphorustrifluoride with p in the center and three f bonding with it.PF5 is phosphoruspentafluoride with p in the middle and 5 f linking to bond
