A valid Lewis structure of IF3 cannot be drawn without violating the octet rule.
Answer: IF3 (Iodine Trifluoride)
This is because, I (Iodine) and F (Fluorine) both have odd number of valence electrons (7) which also means that there are too many valence electrons in the valence shell.
<h3>
Answer:</h3>
0.34 mol S
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
11 g S
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of S - 32.07 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
0.343 mol S ≈ 0.34 mol S
Answer:
Ok to solve this you will need to use the Ideal Gas Law Formula which is as follows:
PV = nRT
P= pressure
V= volume
n= # of moles
R= Universal Gas Constant (0.0821 L x atm/mol x K)
T= Kelvin temperature
1.Simplify the Ideal Gas Law formula to what you need to solve for:
P = (nRT)/ V
2. List all you components as follows (this makes the process easier):
P = ?
V = 45.4 L
n = 0.625 mol
R = 0.0821 L x atm/ mol x K
T = 249 K
To find the Kelvin temperature K = C + 273
3. Plug in all your components in your set up formula:
P = [(0.625 mol)(0.0821 L x atm/ mol x K)(249 K)] / (45.4 L)
4. Cross out all similar units so the only thing left is atm because you are trying to find pressure.
P = [(0.625)(0.0821atm)(249)] / (45.4)
5. Multiply through and simplify
P = 0.28 atm
B. is the correct answer.
Glad I could help!! If you have any other questions just message me. Hopefully this was helpful.
Explanation:
