1. 12 L = 12 dm³
2. 3.18 g
<h3>Further explanation</h3>
Given
1. Reaction
K₂CO₃+2HNO₃⇒ 2KNO₃+H₂O+CO₂
69 g K₂CO₃
2. 0.03 mol/L Na₂CO₃
Required
1. volume of CO₂
2. mass Na₂CO₃
Solution
1. mol K₂CO₃(MW=138 g/mol) :
= 69 : 138
= 0.5
mol ratio of K₂CO₃ : CO₂ = 1 : 1, so mol CO₂ = 0.5
Assume at RTP(25 C, 1 atm) 1 mol gas = 24 L, so volume CO₂ :
= 0.5 x 24 L
= 12 L
2. M Na₂CO₃ = 0.03 M
Volume = 1 L
mol Na₂CO₃ :
= M x V
= 0.03 x 1
= 0.03 moles
Mass Na₂CO₃(MW=106 g/mol) :
= mol x MW
= 0.03 x 106
= 3.18 g
Answer:Search Results
Featured snippet from the web
As the torrent of water dried up for the first time in thousands of years, it revealed a horrific sight. n(CO2) = mass(CO2)/Molar mass(CO2) = 112/44 = 2.5454
Explanation:
<u>The given reaction is:</u>
F2 + ClO2 → 2FClO2
Rate = k[F2][ClO2]
<u>Explanation:</u>
The possible mechanism for this reaction can be broken down into two steps with the slow step being the rate determining step
Step 1: F2 + ClO2 → FClO2 + F ----------- Slow
Step 2: F + ClO2 → FClO2 ----------- Fast
-----------------------------------------------------------
Overall: F2 + 2ClO2 → 2FClO2
Rate = k[F2][ClO2]
Answer:
Water's heat of vaporization is around 540 cal/g at 100 °C. The same amount of heat is exchanged or released in the phase shift during the condensation of 1 g water vapor to 1 g of water.
Explanation:
brainliest?
It's Fluorine (non-metal) whose E.C. is 1s2, 2s2, 2p5
& Cesium (metal) whose E.C. is [Xe] 6s1
