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sashaice [31]
3 years ago
11

Propose a plausible mechanism for the reaction f2 + 2clo2 → 2fclo2 given that the rate law for the reaction is rate = k[f2][clo2

]. click in the answer box to activate the palette. do not include states of matter.
Chemistry
2 answers:
shepuryov [24]3 years ago
8 0

<u>The given reaction is:</u>

F2 + ClO2 → 2FClO2

Rate = k[F2][ClO2]

<u>Explanation:</u>

The possible mechanism for this reaction can be broken down into two steps with the slow step being the rate determining step

Step 1:       F2 + ClO2 → FClO2 + F ----------- Slow

Step 2:      F + ClO2 → FClO2           ----------- Fast

-----------------------------------------------------------

Overall:  F2 + 2ClO2 → 2FClO2

Rate = k[F2][ClO2]

 


ololo11 [35]3 years ago
5 0

Answer:

Step 1: slow dissociation of fluorine (controlling stage):

F_2+ClO_2-->FClO_2+F^-

Step 2: fast chlorine dioxide reaction with fluoride ions:

F^-+ClO_2-->FClO_2

Explanation:

Hello,

The undergoing chemical reaction:

F_2+2ClO_2-->2FClO_2

Could be attained via two steps forming the required plausible mechanism with the given reaction rate:

Step 1: slow dissociation of fluorine (controlling stage):

F_2+ClO_2-->FClO_2+F^-

Step 2: fast chlorine dioxide reaction with fluoride ions:

F^-+ClO_2-->FClO_2

In this case, it is necessary for the fluorine to be dissociated to promote the formation of the two FClO_2 molecules and its consequent simplification as the formed fluorine ions act as intermediates, thus, the overall reaction turn out into:

F_2+2ClO_2-->2FClO_2

Best regards.

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The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound             Amount

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     H₂                        4.77 g

     Fe                        4.38 g

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<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M

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Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

For the given chemical equation:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

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