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3 years ago

How mutch heat do you use to evaporerate warter

Chemistry

2 answers:

WINSTONCH [101]3 years ago

7 0

waters boiling point is 212F or 100C

Free_Kalibri [48]3 years ago

5 0

Answer:

Water's heat of vaporization is around 540 cal/g at 100 °C. The same amount of heat is exchanged or released in the phase shift during the condensation of 1 g water vapor to 1 g of water.

Explanation:

brainliest?

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Solid potassium hydroxide koh decomposes into gaseous water and solid potassium oxide . write a balanced chemical equation for t

galina1969 [7]

<span>The chemical formula is pretty straightforward. 2KOH reacts to produce H2O and K2O. This is the balanced chemical reaction between: Solid potassium hydroxide koh decomposing into gaseous water and solid potassium.</span>

4 0

3 years ago

The balanced equation for combustion in an acetylene torch is shown below: 2C2H2 + 5O2 → 4CO2 + 2H2O The acetylene tank contains

andriy [413]

Answer: 67.2 moles

Explanation: $2C_2H5+5O_2\rightarrow 4CO_2+2H_2O$

According to the given balanced equation, 2 moles of acetylene $C_2H_2$ combine with 5 moles of oxygen $O_2$ to produce 4 moles of carbon dioxide $CO_2$ .

Thus if 2 moles of acetylene $C_2H_2$ combine with = 5 moles of oxygen $O_2$

35 moles of acetylene $C_2H_2$ combine with= $\frac{5}{2}\times {35}=87.5$ moles of oxygen $O_2$

But as only 84 moles of oxygen are available, acetylene is not a limiting reagent.

5 moles of oxygen $O_2$ reacts with = 2 moles of acetylene $C_2H_2$

84 moles of oxygen $O_2$ reacts with= $\frac{2}{5}\times {84}=33.6$ moles of acetylene $C_2H_2$

Thus Oxygen is the limiting reagent as it limits the formation of products. Acetylene is excess reagent as it is present in excess.

2 moles of acetylene $C_2H_2$ produce= 4 moles of carbon dioxide $CO_2$ .

33.6 moles of acetylene $C_2H_2$ produce= $\frac{4}{2}\times {33.6}=67.2$ moles of of carbon dioxide $CO_2$ .

8 0

3 years ago

Read 2 more answers

A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s

Lilit [14]

Answer:

pH = 1.32

Explanation:

H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount to buffer solutions. In the first deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g = 0.074 mol H₂M

54 mL x 1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH

it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.

For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

3 0

3 years ago

Write the coefficients for the reactant and product.

balu736 [363]

<h3>Answer:</h3>

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

<h3>Explanation:</h3>

The equation for the reaction shown represents the combustion of ethane.

C₂H₆ + O₂ → CO₂ + H₂O

To balance the equation we put the coefficients, 2, 7, 4, and 6 on the reactants and products.

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Balancing chemical equations makes the number of atoms of each element equal on both side of the equation.

It ensures that chemical equations obey the law of conservation of mass in chemical reactions.

4 0

3 years ago

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The degree of polarity of a chemical bond in a molecule of a compound can be predicted by determining the difference in the

Alex777 [14]

(3) <span>electronegativities of the bonded atoms in a molecule of the compound is the correct answer.

The compound is nonpolar when</span> electronegativity is from 0 to 0.5, polar when electronegativity is from 0.5 to 1.7, and ionic when electronegativity is larger than 1.7.

Hope this would help~

6 0

3 years ago

Read 2 more answers