Q1
r = (2A/θ)^.5 = ((14/(1/8))^.5 = 10.583 ft <--------
q2
θ = 2A/r^2 = 2*3/7^2 = .122 rad <--------
M+n= 14, and 14/9 equals 1 and 5/9.
Answer:11.5cm, 23cm, 34.5 cm, 69cm
Step-by-step explanation:
1+2+3+6=12
138/12=11.5
First side=11.5cm
Second side=11.5x2=23cm
Third side=11.5x3=34.5cm
Fourth side=11.5x6=69cm
Please Help!!! Calculate the interquartile range for this set of data: {34, 47, 1, 15, 57, 24, 20, 11, 19, 50, 28, 37}
allsm [11]
Let's put it in order.
1, 11, 15, 19, 20, 24, 28, 34, 37, 47, 50, 57
Let's split it in half.
1, 11, 15, 19, 20, 24║28, 34, 37, 47, 50, 57
17 42
42-17
25
The IQR is C) 25.
Answer:
y = 3x/2
Step-by-step explanation:
Let's solve for y first.
3y = -2x+6
y = -2x/3 + 2
We know that the slope is perpendicular to -2/3, meaning that we have to find the negative reciprocal of -2/3, which is 3/2.
y = 3x/2 + C.
We know the point (2, 3) and we plug that into our equation above.
3 = 3/2(2) + C.
3 = 3 + C
0 = C
C = 0.
We now plug in C for the equation, which gives us y = 3x/2.
