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3 years ago

If you have 5\6 of a cup of flour, how many twelfths do you have

Mathematics

1 answer:

egoroff_w [7]3 years ago

6 0

Answer:

10/12

Step-by-step explanation:

Multiply 5/6x2/2

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1. When the point is reflected over x-axis, what will the new coordinates of the new point be?

stich3 [128]

Answer:

(x , y) ----> (-x , y)

Step-by-step explanation:

(x , y) ----> (-x , y)

Example for 1. :

(-4,2) ---> (4,2)

4 0

3 years ago

2) A rectangular pyramid has the base area measuring 30 m by 20 m. Given 1 point

Hitman42 [59]

Answer:

20x30xH=7000

11.6666 , depends on how much you need to round it. if 2 sig figs, round it to 12.

4 0

3 years ago

Read 2 more answers

Andrew calculates that 40 % 40% of 50 % 50% of x x is equal to 20 % 20% of 30 % 30% of y y, where x ≠ 0 x≠0. Which of the follow

Shtirlitz [24]

Answer:

Step-by-step explanation:

8 0

3 years ago

What is meant by the term 'domain'?

damaskus [11]

B the set of input values for the function.

4 0

3 years ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0

3 years ago