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Damm [24]
3 years ago
14

Explain briefly why the deposition rate is linearly proportional to the square- root of the flow rate at low flow-rates.

Engineering
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

Chemical Vapor Deposition (CVD) alludes to a class of techniques where a strong is developed by response of vaporous source materials and yielding an item emanating gas. There are various variations on the cycle in light of the weight territory at which it is directed, the kind of reactants, and whether some strategy to actuate the response is utilized. CVD can likewise be directed in a nuclear layer testimony (ALD) mode in which single layers of molecules are created each in turn. CVD has a number of points of interest over actual fume testimony. For instance, the response can frequently be organized to be particular all the more effectively, saving material just in specific districts of the substrate as opposed to covering it

with a sweeping layer. CVD is commonly more conformal than physical fume statement, implying that it covers an unpleasant surface generally

Explanation:

consistently, following the morphology as opposed to bringing about meager, low quality coatings on vertical dividers of the substrate, just like the case for actual fume statement strategies. Different focal points incorporate that CVD utilizes source materials that stream into the cycle chamber from outside supplies that can be topped off without tainting of the development climate, it doesn't need exceptionally high vacuum levels, it can for the most part measure substrates in bigger bunches than dissipation, and is additional easy-going as far as its capacity to bear accuracy simultaneously conditions. Counterbalancing these focal points, CVD source materials are commonly profoundly harmful or combustible, requiring extraordinary consideration in the plan and activity of a CVD cycle framework. CVD additionally regularly requires high temperatures. For microelectronics fabricating the benefits by and large exceed the issues.

It is critical to gauge the right vanishing pace of Alq3 in our reproduction, however it is troublesome on the grounds that the right worth relies upon the surface territory of the natural material, the temperature, the transporter gas stream, etc. In this way, we gauge observational it utilizing an enthalpy of vanishing that has gotten by the examination.

The transporter gas stream rate in our model is sufficiently high to treat the dissipation cycle as motor. On account of motor vanishing system, a fume re-consolidate rate is adequately low contrasted and a dissipation rate.

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NeTakaya

Answer:

Product dissection has been widely deployed in engineering education as a means to aid in student's understanding of functional product elements, development of new concept ideas, and their preparation for industry.

Explanation:

I hope this helps :) have a wonderful day!

6 0
3 years ago
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The uniform beam is supported by two rods AB and CD that have crosssectional areas of 10 mm2 and 15 mm2 , respectively. Determin
ddd [48]

Answer:

w=2.25

Explanation:

It is necessary to determine the maximum w so that the normal stress in the AB and CD rods does not exceed the permitted normal stress.  

The surface of the cross-section of the stapes was determined:  

A_ab= 10 mm^2

A-cd=  15 mm^2

The maximum load is determined from the condition that the normal stresses is not higher than the permitted normal stress σ_allow.

σ_ab = F_ab/A_ab\leqσ_allow

σ_cd =  F_cd/A_cd\leqσ_allow

In the next step we will determine the static size: Picture b).  

We apply the conditions of equilibrium:  

∑F_x=0

∑F_y=0

  ∑M=0

∑M_a=0 ==> -w*6*0.5*6*0.75*F_cd*6 =0

              ==> F_cd = 2*w*k*N

∑F_y=0 ==> F_cd+F_ab - 6*w*0.5 ==>2*w+F_ab -6*w*0.5 =0

              ==> F_ab = w*k*N

Now we determine the load w  

<u>Sector AB:  </u>

σ_ab = F_ab/A_ab\leq σ_allow=300 KPa

         = w/10*10^-6\leq σ_allow=300 KPa

w_ab = 3*10^-3 kN/m

<u>Sector CD:  </u>

σ_cd = F_cd/A_cd\leq σ_allow=300 KPa

         = 2*w/15*10^-6\leq σ_allow=300 KPa

w_cd = 2.25*10^-3 kN/m

w=min{w_ab;w_cd} ==> w=min{3*10^-3;2.25*10^-3}

                                ==> w=2.25 * 10^-3 kN/m

<u>The solution is:  </u>

                                w=2.25 N/m

note:

find the attached graph

6 0
3 years ago
Alberto's mom is taking a splinter out of his hand with a pair of tweezers. The tweezers are 3 inches long. She is applying .25
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Answer:

ok

Explanation:

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5 0
4 years ago
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Which one of these is NOT considered a skill?
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Answer:

number 2 people skills

Explanation:

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4 0
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1.identify two major inventions or innovations related to each engineering and technology pathway
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Explanation:

Things related to engineering:

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