Sponges, sea stars, annelid worms, molds and lichens are some of the organisms that can reproduce using the process of fragmentation.
In general division of the nucleus is by the s stage of interphase and is often accompanied by cytokinesis which divides the cytoplasm organelles and cell membrane into two new cells containing roughly equal shares of these cellular components .
Answer:
Enzymes are biocatalysts which increases the rate of the biochemical reaction by lowering the activation energy of the reaction.
It performs the catalysis in four steps:
- The substrate enters the active site of a specific enzyme. The specificity is determined by shape complementarity and non-covalent interactions such as hydrophobic interactions.
- These interactions bring some changes in the shape of the active site of the enzyme which results in the formation of the enzyme-substrate complex.
- The process of catalysis takes place by which the substrate is converted into the product. It includes the breaking or rearrangement of old bonds and formation of new bonds. It results in the formation of enzyme-product complex.
- The product has different properties as compared to the substrate due to which it gets released from the active site of the enzyme. The free enzyme is ready to initiate a new cycle.
Thus, the correct answer would be the formation of the enzyme-substrate complex.
Answer:
N = 187.55
Explanation:
Here you just need to replace the terms and clear the equation.
You already know that,
- First capture: 25 prairie dogs.
- First marked animals: 25 (the whole first capture)
You let these animals leave and then you made another capture.
- Second capture: 135 prairie dogs
- Already Marked animals: 18 (these 18 dogs were caught in the first capture and marked before releasing them)
To know the size of the prairie dogs population you just need to use the following equation and clear N, which is the value that you are looking for.
Number of individual marked in first catch/Total population size, N = Number of individual marked in 2nd catch / Total number of 2nd catch
- Number of individual marked in first catch = 25 dogs
- Total population size, N = this is what we want to know
- Number of individual marked in 2nd catch = 18 dogs
- Total number of 2nd catch = 135 dogs
So now, we need to replace terms
25 / N = 18 / 135
25 / N = 0.1333
N = 25 / 0.1333
N = 187.55
Answer:
A
Explanation:
This is called the locus and is determined in Meiosis by gametes from parent cells. During meiosis there is this thing called 'crossing over' where the gametes (sperm and egg cells) homologous genes (genes of similar size and shape, such as X and Y chromosomes or X and X) exchange genes on the same locus to provide slightly different characteristics.
Please check this with your teacher but i believe that this is right. Hope this helps. ;)
