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MrRa [10]
3 years ago
10

ANSWER PLZ QUICK AND FAST

Mathematics
1 answer:
kherson [118]3 years ago
3 0

Half of n, is option D, n/2.

This is because if you divide something by 2, you are dividing it in half.

Hope this helps!

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I HAVE A FEW MINS PLEASE HEELPPP! FOR BRIANLIEST!
riadik2000 [5.3K]

Answer:

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is 6/36 = 1/6

8 0
2 years ago
Question 12 Multiple Choice Worth 1 points)
Alex777 [14]

Answer:

96?

Step-by-step explanation:

I just did 32 times 3 and got 96, it might not be right but it's what I got with what I did

3 0
2 years ago
The shape of the distribution of the time required to get an oil change at a 20 minute oil change facility. However, records ind
Katyanochek1 [597]

Answer:

For a mean oil change time of 20.51 minutes there would be a​ 10% chance of being at or​ below

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 21.3, \sigma = 3.9, n = 40, s = \frac{3.9}{\sqrt{40}} = 0.6166

Treating this as a random​ sample, at what mean​ oil-change time would there be a​ 10% chance of being at or​ below?

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.28 = \frac{X - 21.3}{0.6166}

X - 21.3 = -1.28*0.6166

X = 20.51

For a mean oil change time of 20.51 minutes there would be a​ 10% chance of being at or​ below

6 0
3 years ago
VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.
jonny [76]

Answer:

he action or condition of becoming or being made wider, larger, or more open.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Annika has a circular garden with a radius of 14 feet. One fourth of the garden is planted with yellow roses. what is the area n
Brilliant_brown [7]

Answer:A

Step-by-step explanation:

3/4*22/7*14^2

=3/4*22/7*14*14

=3*11*2*7

=33*2*7

=66*7

=462

4 0
2 years ago
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