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Arisa [49]
3 years ago
15

Launch Problem

Mathematics
1 answer:
Maurinko [17]3 years ago
7 0

Answer:

A) 6

B) 2 Pencils,1 Eraser,3 Stickers.

Step-by-step explanation:

Hope this helps!

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✨a Pls help I will park you as brainlist promise ✨✨
svlad2 [7]
A. I am pretty sure that is right
4 0
2 years ago
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HELP!
Readme [11.4K]

Answer: You have a better chance if you do not replace the red marble.

Step-by-step explanation:

The bag has:

5 red marbles

8 blue marbles

4 yellow marbles

3 green marbles

A total of 5 + 8 + 4 + 3 = 20

You want to draw a red marble and then a blue marble.

The probability of drawing a red marble in your first attempt is the number of red marbles divided the total number of marbles:

P1 = 5/20  

now you want to draw a blue marble.

If you replace the red marble, you have 20 marbles again in the bag, then the probability of drawing a blue marble is:

P2 = 8/20

The joint probability is P = P1*P2 = (5/20)*(8/20) = 0.1

If you do not replace the red marble, you have 19 total marbles in the bag, then the probability of taking a blue marble is:

P2 = 8/19

The joint probability is:

P = P1*P2 = (5/20)*(8/19) = 0.105

The probability is slightly bigger if you do not replace the red marble.

7 0
3 years ago
Read 2 more answers
Which side lengths cannot form a triangle?
sineoko [7]

Answer:

answer is option A

A, 4+12>6✓

12+6>4✓

4+6>12×

because sum of two sides lengths ina a triangle should greater than the other side's length

5 0
3 years ago
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I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
3 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST
Digiron [165]

Answer:

6 mm  slope 3

Step-by-step explanation:

4 0
3 years ago
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