You are looking toronto corto go to Macon and back (210 mites)

What is 5(6p+8)=30p+7+7

Soloha48 [4]

Answer:

There are no solutions.

Step-by-step explanation:

add the like terms

then the distribute the 5 and 8

subtract from both sides

then you will see the answer is no solutions

4 0

2 years ago

Keira , larry and gita picked apples at an orchard. keira picked twice as many pounds as larry and 3 times as many as gita. the

Natalija [7]

Number of apples in pounds picked up by Keira = K
Number of apples in pounds picked up by Larry = L
Number of apples in pounds picked up by Gita = G
Total number of apples they picked all together in pounds = 8360
Now from the given question, we know
Number of apples picked up by Kiera = 2L
So
K = 2L
L = K/2
Again Kiera picked up 3 times as many apples as Gita picked.
So,
K = 3G
G = K/3
Now if we add all the apples in pounds picked up by the three of them.
Then
K + L + G = 8360
K + (K/2) + K/3) = 8360
(6K + 3K + 2K)/6 = 8360
11K/6 = 8360
11K = 8360 * 6
11K = 50160
K = 4560
Then
L = K/2
   = 4560/2
   = 2280
G = K/3
   = 4560/3
   = 1520
Now we can say that
Kiera picked 4560 pounds of apple
Larry picked 2280 pounds of apple
Gita picked 1520 pounds of apple

7 0

2 years ago

Please answer asap I really need it til 2.00 p.m, A sporting good store manager was selling a ski set for a certain price. The m

coldgirl [10]

Answer:

the ski original price is 641

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Which is bigger, 7/8" or 9/16"?

Iteru [2.4K]

7/8 and 9/16

7*2/8*2 = 14/16

14/16 and 9/16

Now since we have a common denominator, we can compare the numerators.

14/16 is greater, so 7/8 is greater than 9/16

Answer: 7/8 is bigger

5 0

3 years ago

Read 2 more answers

mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma

Aneli [31]

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: $r= \frac{c^2}{8m} + \frac{m}{2}$
where
$c$ is the length of the chord
$m$ is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so $c=52$ and $m=6$ . Lets replace those values in our formula:
$r= \frac{52^2}{8(6)} + \frac{6}{2}$
$r= \frac{2704}{48} +3$
$r= \frac{169}{3} +3$
$r= \frac{178}{3}$

Next, to find the minimum speed, we are going to use the formula: $s= \sqrt{15fr}$
where
$f$ is <span>drag factor
</span> $r$ is the radius
We know form our problem that the drag factor is 0.2, so $f=0.2$ . We also know from our previous calculation that the radius is $\frac{178}{3}$ , so $r= \frac{178}{3}$ . Lets replace those values in our formula:
$s= \sqrt{(15)(0.2)( \frac{178}{3}) }$
$s= \sqrt{178}$
$s=13.34$ mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.

8 0

3 years ago