This can be solved using a system of equations.

Subtract y from both sides.

Substitute:

Subtract 80 from both sides:

Divide both sides by 5:

Substitute.
24/7 = 180/x....24 ft to 7 seconds = 180 ft to x seconds
cross multiply
(24)(x) = (180)(7)
24x = 1260
x = 1260/24
x = 52.5....so it will take 52.5 seconds
It would $17.47. if you times $4.99 by 3.5 pounds of cherries then your answer will be $17.47
Answer:
Non Linear
Step-by-step explanation:
Its non-linear because when you put X to the second power, it will change the function into a quadratic function
Answer:

Step-by-step explanation:
1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

3) To test it, just integrate:
