Question

What pressure would be required to take 100.0 ml of a gas at 103.0 kPa and squish it down to 2.00 ml

Answer 1

Answer:

5150 kPa

Explanation:

Given that,

Initial volume, V₁ = 100 mL

Initial pressure, P₁ = 103 kPa

Final volume, V₂ = 2 mL

We need to find the new pressure of the gas. The relation between the pressure and the volume of gas is given by :

$P_1V_1=P_2V_2\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{103\times 100}{2}\\\\P_2=5150\ kPa$

So, the new pressure is 5150 kPa.