The half-life of a radioactive compound is the time taken for that said isotope to decay or disintegrate so that only half of the initial atoms remain in that compound. During the decay process, the isotope will give off energy and matter, and the way to depict this is indicated by t 1/2.
Answer:
20.79 kilojoules
Explanation:
Using Q = m×c×∆T
Where;
Q = Quantity of heat (J)
c = specific heat capacity of solid DMSO (1.80 J/g°C)
m = mass of DMSO
∆T = change in temperature
According to the provided information, m= 50g, initial temperature = 19.0°C, final temperature= 250.0°C
Q = m×c×∆T
Q = 50 × 1.80 × (250°C - 19°C)
Q = 90 × 231
Q = 20790 Joules
To convert Joules to kilojoules, we divide by 1000 i.e.
20790/1000
= 20.79 kilojoules
Hence, 20.79 kilojoules of energy is required to convert 50.0 grams of solid DMSO to gas.
Answer:
It is referred to as the van't Hoff factor.
Explanation:
The van't Hoff factor is named after the Dutch chemist Jacobus Henricus van 't Hoff. It can also be defined as the ratio of the actual quantity of particles to the quantity of particles for no ionization.The fundamental assumption of the van't Hoff factor is that the substance is a nonelectrolyte.
Answer:
the action or power of focusing one's attention or mental effort.
Explanation:
