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3 years ago

44 = t - 10; 52, 53, 54

Mathematics

1 answer:

trapecia [35]3 years ago

7 0

The answer is 54 pls mark brainliest if correct

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How does the number of zeros in the product eight and five thousand compare to the number of zeros in factors? Explain.

Flura [38]

8X5000 is 40000. There's three zeroes in5000 and no zeroes in 8, yet there are 4 zeroes in the answer. This is because you must multiply the non-zeroes, and then add the zeroes from your factors. 8 times 5 is 40, add 3 zeroes to get 40000.
Hope this helps!

7 0

3 years ago

100 point please help

Allushta [10]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The line having an x intercept of 3 and y intercept of 10<br> Write this in Standard form Ax+By=C

Svetlanka [38]

Answer:

The standard form of the line is 10x + 3y = 10

Step-by-step explanation:

First we need to find the slope of the equation, which we can do using the slope equation and the two points given: (3, 0) and (0, 10)

m(slope) = (y2 - y1)/(x2 - x1)

m = (10 - 0)/(0 -3)

m = 10/-3

Now we can write the equation in slope intercept form since we have the slope and the intercept.

y = mx + b

y = -10/3x + 10

Now we can manipulate the equation to get the standard form.

y = -10/3x + 10

10/3x + y = 10

10x + 3y = 30

5 0

3 years ago

Simplify the following expression:<br> Sqrt (-16) + sqrt(-25+5)

Studentka2010 [4]

Answer:

(4 + 2√5) i

Step-by-step explanation:

√(-16) + √(-25 + 5)

√(-16) + √(-20)

4i + 2i√5

(4 + 2√5) i

7 0

3 years ago

Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

3 0

3 years ago