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Oksi-84 [34.3K]
3 years ago
5

Jason and his children went into a movie theater where they sell drinks for $4 each and pretzels for $5 each. Jason has $65 to s

pend and must buy at least 14 drinks and pretzels altogether. If
x
x represents the number of drinks purchased and
y
y represents the number of pretzels purchased, write and solve a system of inequalities graphically and determine one possible solution.
Mathematics
2 answers:
saw5 [17]3 years ago
8 0

Answer:

Jason could buy 13 drinks and 2 pretzels.

Step-by-step explanation:

The inequalities are:

y ≥ 14 − x

by shading up and graph

y ≤ 13 - 4/5x

by shading down

klemol [59]3 years ago
4 0

Answer:

Number of drink = 5

Number of pretzel = 9

Step-by-step explanation:

Given:

Cost of each drink = $4

Cost of each pretzel = $5

Total money = 65

Total number of drink and pretzel = 14

Find:

Number of drink and pretzel

Computation:

Number of drink = x

Number of pretzel = 14 - x

So,

x(4) + (14-x)5 = 65

4x + 70 - 5x = 65

x = 5

Number of drink = 5

Number of pretzel = 14 - x

Number of pretzel = 14 - 5 = 9

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snow_tiger [21]

We can notice from the figure that : Area of the home plate is equal to sum of the Area of the rectangle ( 8 in x 15 in) and Area of the triangle with height 6 in and base 15 in.

Area of the rectangle : Length x Width

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3 0
3 years ago
Below are the jersey numbers of 11 players randomly selected from a football team. Find the​ range, variance, and standard devia
jeyben [28]

Answer:

The range is 77.

The variance is 739.8.

The standard deviation is 27.2.

Step-by-step explanation:

The data provided, in ascending order is as follows:

S = {11 , 14 , 23 , 31 , 40 , 60 , 63 , 68 , 75 , 77 , 88}

The range of a data set is the difference between the maximum and minimum values.

From the above data set we know,

Maximum = 88

Minimum = 11

Compute the range as follows:

Range = Maximum - Minimum

           = 88 - 11

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The range is 77.

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum x_{i}=\frac{1}{11}\times [11+14+23+...+88]=50

Compute the variance as follows:

\sigma^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x})^{2}

    =\frac{1}{11-1}\times [(11-50)^{2}+(14-50)^{2}+...+(88-50)^{2}]\\\\=\frac{1}{10}\times 7398\\\\=739.8

The variance is 739.8.

Compute the standard deviation as follows:

\sigma=\sqrt{\frac{1}{n-1}\sum (x_{i}-\bar x})^{2}}=\sqrt{739.8}=27.199265\approx 27.2

The standard deviation is 27.2.

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3 years ago
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