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2 years ago

Which best explains how the body maintains homeostasis?

Chemistry

1 answer:

MissTica2 years ago

4 0

B. each system works independently to stabilize the body

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Snap me r.alivia05 also no creepy old men, just nice females

AnnyKZ [126]

Answer:

this is hella sus

Explanation:

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3 years ago

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What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

Mashutka [201]

Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

6 0

3 years ago

5.0 x 10^24 molecules equal

Ratling [72]

4.999999999999999e+24 this is what i got on the calculator but i dont know if its right.

8 0

2 years ago

How many grams of CO2 are in 3.6 mol of CO2?

hammer [34]

There are 158.4 grams of CO2 in 3.6 mol of CO2.

<h3>HOW TO CALCULATE MASS?</h3>

The mass of a substance can be calculated by multiplying the number of moles of the substance by its molar mass. That is;

mass of CO2 = no. of moles × molar mass

According to this question, there are 3.6 moles of CO2.

mass of CO2 = 3.6 moles × 44g/mol

mass of CO2 = 158.4g.

Therefore, there are 158.4 grams of CO2 in 3.6 mol of CO2

Learn more about mass at: brainly.com/question/15959704

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2 years ago

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An exhaled air bubble underwater at 290.

Vinil7 [7]

The answer for the following problem is mentioned below.

Therefore the final volume of the gas is 52.7 ml.

Explanation:

Given:

Initial pressure ( $P_{1}$ ) = 290 kPa

Final pressure ( $P_{2}$ ) = 104 kPa

Initial volume ( $V_{1}$ ) = 18.9 ml

To find:

Final volume ( $V_{2}$ )

We know;

From the ideal gas equation;

P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of gas

n represents the no of the moles

R represents the universal gas constant

T represents the temperature of the gas

So;

P × V = constant

P ∝ $\frac{1}{V}$

From the above equation;

$\frac{P_{1} }{P_{2} } = \frac{V_{2} }{V_{1} }$

$P_{1}$ represents the initial pressure of the gas

$P_{2}$ represents the final pressure of the gas

$V_{1}$ represents the initial volume of the gas

$V_{2}$ represents the final volume of the gas

Substituting the values of the above equation;

$\frac{290}{104}$ = $\frac{V_{2} }{18.9}$

$V_{2}$ = 52.7 ml

Therefore the final volume of the gas is 52.7 ml.

6 0

2 years ago