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givi [52]
3 years ago
14

A solution contains 35 grams of KNO3 dissolved in 100 grams of water at 40°C. How much more KNO3 would have to be added to make

it a saturated solution?
(1) 29 g (3) 12 g
(2) 24 g (4) 4 g
Chemistry
2 answers:
Anna71 [15]3 years ago
6 0
The answer is (1) 29 g. The solubility means that one compound can be dissolved in 100 grams of water. The solubility of KNO3 under 40℃ is 64 g. So 64-35=29 grams of KNO3 needs to be added.
MakcuM [25]3 years ago
4 0

The solubility of  at 40 C is around 64 g in 100 g water  ot 0.64 g KNO3 in 100 g water.  

Therefore 64 g KNO3  in 100 g water is required for satured solution.

 According to the problem  there are 35 grams of KNO3 dissolved in 100 grams  water  

So we need 64 g-35 g= 29 g more KNO3  

Hence the correct answer is 1  

Solubility:

When the maximum amount of solute is dissolve in the solvent is called solubility. On the basic of solubility the solution are following types:

Saturate solution:

A solution which contains the maximum amount of dissolved solute at the equilibrium is called saturated solution.  

Un-saturate solution:

A solution which contains lesser amount of solute as compare to saturated solution.  It will be able to dissolver more solute.  

Super -Saturate solution:

A solution which contains the more dissolved amount of solute as compare to saturated solution.

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water is also binary because it is also made up of only two elements hydrogen and oxygen.

In given question it is stated that the charge of cation is twice than the anion which means its charge would be +2 thus anionic part will have the charge -1. In neutral compound the positive and negative charges must be equal in magnitude to cancel the effect of each other and make the compound neutral. So, there must be two anionic atom present so that charge becomes -2 and cancel the +2 charge of cationic part. Thus the formula will be,

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