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Law Incorporation [45]
3 years ago
6

Rob and john share money in a ratio of 9:4. How much of the £39000 does john get ?

Mathematics
1 answer:
murzikaleks [220]3 years ago
3 0
\bf \cfrac{Rob}{John}\qquad 9:4\qquad \cfrac{9}{4}\qquad \cfrac{9\cdot \frac{39000}{9+4}}{4\cdot \frac{39000}{9+4}}\implies \cfrac{9\cdot 3000}{4\cdot 3000}
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A cylindrical tank has a radius of 15 ft. and a height of 45 ft. How many cubic feet of water can the tank hold?
Likurg_2 [28]
<span>To calculate the amount of water the cylindrical tank can hold the volume of cylindrical tank needs to be calculated. The volume of cylindrical tank can be calculated with the following formula:
Volume = π x (radius of cylinder) x (radius of cylinder) x (height of cylinder)
or in short, V = πr(square)h
We have all the variables available, as radius is 15 ft and height is 45 ft the volume would be π*15*15*45 = 31808.63 cubic ft (using the approximated value of π as 3.14159).
The volume of water the tank can hold would be equal to the volume of the tank or 31808.63 cubic ft.</span>
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Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative
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5 0
3 years ago
The point (-3/5,y)in the third quadrant corresponds to angle θ on the unit circle.
anastassius [24]
The given point (-3/5 , y) lies in the third quadrant.
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For a point (x,y) lying on a unit circle a and y are defined as:

x = cos θ
y = sin θ

So, we can say for the point (-3/5 , y) the value -3/5 is equal to cos θ

sec θ is the reciprocal of cos θ.

So, sec θ = -5/3

cot\theta= \frac{cos\theta}{sin\theta}

Using Pythagorean identity we can first find sin θ.

sin \theta = - \sqrt{1- cos^{2}\theta }  \\  \\ &#10;sin\theta= \sqrt{1-( -\frac{3}{5})^{2} }=-  \frac{4}{5}

Since the point lies in 3rd quadrant, both sin and cos will be negative.

So, now we can write:

cot\theta= \frac{ \frac{-3}{5} }{ \frac{-4}{5} } \\  \\ &#10;cot\theta= \frac{3}{4}

Answers:
sec θ = -5/3
cot θ = 3/4
8 0
3 years ago
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sweet [91]

Answer:

Where is a questionn? How can I answer you if you don't have a question

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