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3 years ago

Im going to say the n word

Mathematics

2 answers:

max2010maxim [7]3 years ago

7 0

I honestly don’t care that’s on youuuu!

Gennadij [26K]3 years ago

4 0

Answer:

Don't

Step-by-step explanation:

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Who ever answers first will be marked brainliest

jenyasd209 [6]

Answer:

The answer is x≥9.

Step-by-step explanation:

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3 years ago

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The speed of sound is approximately 768 miles per hour. When an object travels faster than the speed of sound, it creates a soni

lawyer [7]

S>768=sonic boom........

8 0

3 years ago

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For the case of 5-item order, how many different ways are there to place an order? For Each case, list the number of wheels that

Nata [24]

Answer:

Follows are the description of the given point:

Step-by-step explanation:

Please find the correct question in the attached file.

In point A:

An order of 5 items shall be placed in a total of 6 different ways.

(w for cars and ts and tricycles to be used)

$\to 5w=20 wheels\\\\\to 4w+1t= 19 wheels\\\\\to 3w+2t=18 wheels\\\\\to 2w+3t=17 wheels\\\\\to 1w+4t= 16 wheels\\\\\to 5t=15 wheels\\\\$

In point B:

2 waggons so more tyres would be required if they ordered any more waggons.

$work: \\\\ \to 2 \times 4=8 \\\\ \to 3 \times 3=9 \\ \\ \to 8+9=17$

8 0

3 years ago

Can someone please help me ? i will mark brainliest plesase

____ [38]

Answer:

C. Obtuse

Step-by-step explanation:

An obtuse triangle is a triangle with one obtuse angle and two acute angles.

5 0

3 years ago

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Which expression is a sum of cubes?

erik [133]

we know that

A polynomial in the form $a^{3} +b^{3}$ is called a sum of cubes

Let's verify each case to determine the solution

case A) $-64x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-64=-4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case A) is not a sum of cubes

case B) $-32x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-32=-2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case B) is not a sum of cubes

case C) $32x^{6} y^{12} +125x^{9} y^{3}$

we know that

$32=2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

therefore

the case C) is not a sum of cubes

case A) $64x^{6} y^{12} +125x^{9} y^{3}$

we know that

$64=4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

Substitute

$4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}$

$(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}$

therefore

the answer is

$64x^{6} y^{12} +125x^{9} y^{3}$ is a sum of cubes

6 0

3 years ago

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