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Leokris [45]
3 years ago
12

Im going to say the n word

Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0
I honestly don’t care that’s on youuuu!
Gennadij [26K]3 years ago
4 0

Answer:

Don't

Step-by-step explanation:

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jenyasd209 [6]

Answer:

The answer is x≥9.

Step-by-step explanation:

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The speed of sound is approximately 768 miles per hour. When an object travels faster than the speed of sound, it creates a soni
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S>768=sonic boom........
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For the case of 5-item order, how many different ways are there to place an order? For Each case, list the number of wheels that
Nata [24]

Answer:

Follows are the description of the given point:

Step-by-step explanation:

Please find the correct question in the attached file.

In point A:

An order of 5 items shall be placed in a total of 6 different ways.  

(w for cars and ts and tricycles to be used)

\to 5w=20 wheels\\\\\to  4w+1t= 19 wheels\\\\\to  3w+2t=18 wheels\\\\\to  2w+3t=17 wheels\\\\\to  1w+4t= 16 wheels\\\\\to  5t=15 wheels\\\\

In point B:

2 waggons so more tyres would be required if they ordered any more waggons.  

work: \\\\ \to  2 \times 4=8 \\\\  \to 3 \times 3=9 \\ \\  \to 8+9=17

8 0
3 years ago
Can someone please help me ? i will mark brainliest plesase
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Answer:

C. Obtuse

Step-by-step explanation:

 An obtuse triangle is a triangle with one obtuse angle and two acute angles.

5 0
3 years ago
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Which expression is a sum of cubes?
erik [133]

we know that

A polynomial in the form a^{3} +b^{3} is called a sum of cubes

so

Let's verify each case to determine the solution

<u>case A)</u> -64x^{6} y^{12} +125x^{16} y^{3}

we know that

-64=-4^{3}

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{16}=x^{15} *x=x*(x^{5})^{3} -------> is not a perfect cube

y^{3}= (y)^{3}

therefore

the case A) is not a sum of cubes

<u>case B)</u> -32x^{6} y^{12} +125x^{16} y^{3}

we know that

-32=-2^{5} -------> is not a perfect cube

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{16}=x^{15} *x=x*(x^{5})^{3} -------> is not a perfect cube

y^{3}= (y)^{3}

therefore

the case B) is not a sum of cubes

<u>case C)</u> 32x^{6} y^{12} +125x^{9} y^{3}

we know that

32=2^{5} -------> is not a perfect cube

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{9}=(x^{3})^{3}

y^{3}= (y)^{3}

therefore

the case C) is not a sum of cubes

<u>case A)</u> 64x^{6} y^{12} +125x^{9} y^{3}

we know that

64=4^{3}

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{9}=(x^{3})^{3}

y^{3}= (y)^{3}

Substitute

4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}

(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}

therefore

<u>the answer is</u>

64x^{6} y^{12} +125x^{9} y^{3} is a sum of cubes

6 0
3 years ago
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