The formula for the distance from a point (x, y, z) to the plane ax +by +cz +d = 0 is this:
.. distance = |ax +by +cz +d|/√(a^2 +b^2 +c^2)
For your point and plane, that is
.. distance = |-8 -2*7 -4*6 -8|/√(1^2 +2^2 +4^2)
.. = 54/√21
.. = (18/7)√21
Yes the answer is A. Good job!!!
Answer:
if you were looking for the solution i think it is Solution
5
+
1
2
Step-by-step explanation:
Answer:
X=40°
X=30°
X=50°
Step-by-step explanation:
Let our unknown angles be denoted by 
Part I
We are given the sum of the angles as 70°, the known as 30° and the unknown as X;
To find X, we subtract the known angle from the sum as:
X=70°-30°=40°
Hence X= 40°
Part II
We are given the sum of the angles as 70°, the known as 40° and the unknown as X;
To find X, we subtract the known angle from the sum as:
X=70°-40°=30°
Hence X= 30°
Part III
We are given the sum of the angles as 80°, the known as 30° and the unknown as X;
To find X, we subtract the known angle from the sum as:
X=80°-30°=50°
Hence X= 50°
Those addends are in the same order on the left and right, only the parentheses have changed. That's the
Associative Law of Addition