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marishachu [46]
3 years ago
12

Hellloooooooooo am there with uu​

Physics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

hiiiiiiiiiiiii

ohhhkkkaayyyy

vaieri [72.5K]3 years ago
4 0

Answer: this isn't a question

Explanation:

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A machine can never be 100% efficient because some work is always lost due to which factor?
Pachacha [2.7K]

Answer:

A. can never be efficient due to friction

8 0
3 years ago
Read 2 more answers
Investigations allow for the control of variables.
Mila [183]
Dependent / Response Variable: factor or condition in a experiment that changes as a result of the independent variable; often called the responding variable. ... Constant: factors or conditions in an experiment that are kept the same in as trials of the experiment. Control: a set up without the variable being tested.

 
6 0
3 years ago
Two physics students are standing on skateboards and facing each other. Their masses, including the skateboards, are 95 kg and 5
andrey2020 [161]

Answer:

1) \sum \vec p=0\ kg.m.s^{-1}

2) v_2=55.078\ m.s^{-1}

Explanation:

Given:

  • mass of heavier student, m_1=95\ kg
  • mass of lighter student, m_2=58\ kg
  • velocity of the heavier student after the mutual push, v_1=3.1\ m.s^{-1}

1)

Since they push each other and we are neglecting any friction that means we can consider this as a perfectly elastic collision. So the momentum of the two bodies will be equal and in opposite direction.

Since momentum is a vector quantity so the total momentum of the system as a whole will be zero.

2)

<u>From the condition of elastic collision:</u>

p_1=p_2

m_1.v_1=m_2.v_2

95\times 3.1=58\times v_2

v_2=55.078\ m.s^{-1}

6 0
4 years ago
A 1500 kg car traveling east at 40 km/hr turns a corner and speeds up to a velocity of 50 km/hr due north. What is the change in
AlexFokin [52]

Answer:

Change in momentum is 2.667\times 10^{4} kg.m/s

Solution:

The momentum of any body is the product of its mass and the velocity associated with the body and is generally given by:

\vec{p} = m\vec{v}

Now, as per the question:

Mass of the car, M = 1500 kg

The velocity in the east direction, v\hat{i} = 40\hat{i} km/h

The velocity in the north direction, v\hat{j} = 50\hat{j} km/h

Now, the momentum of the car in the east direction:

p\hat{i} = mv\hat{i} = 1500\times 40\hat{i} = 60000\hat{i} kg.km/h

Now, the momentum of the car in the north direction:

p\hat{j} = mv\hat{j} = 1500\times 50\hat{j} = 75000\hat{j} kg.km/h

Change in momentum is given by:

\Delta p = p\hat{i} - p\hat{j} = 60000\hat{i} - 75000\hat{j}

Now,

|\Delta p| = |60000\hat{i} - 75000\hat{j}|

|\Delta p| = \sqrt{60000^{2} + 75000^{2}}

|\Delta p| = 96046 kg.km/hr = \frac{96046}{3.6} = 2.667\times 10^{4} kg.m/s

(Since, 1kg.km/h = \frac{1}{3.6} kg.m/s)

4 0
3 years ago
Confused on how to do this
Nesterboy [21]

Verrrry interesting !

The curves are identical.  That means that at every instant of time, the ball's horizontal and vertical displacement are equal.  

That means that however high off the floor it is, it's exactly the same distance from the wall !

The ball is moving along a 45° diagonal path.  It's like one of those contraptions with a ball connected to a wooden paddle by a rubber band.  Any direction you hit the ball with the paddle, it goes out in that direction, and then it comes right back to the paddle.

-- This ball begins at (0,0) ... where the wall meets the floor.

-- For the first 3 seconds, it goes straight out at a 45° angle. However far from the wall it is, it's exactly the same distance up from the floor.

-- After 3 seconds, it's 4 meters from the wall and 4 meters above the floor.  It's at the point (3, 4) on both graphs.

-- Then it stops going out, and comes back.

-- After 6 seconds, it's back at the point (0, 0) again, where the wall meets the floor.

6 0
3 years ago
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