The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.
The correct option is D.
<h3>What is a quadratic equation ?</h3>
A quadratic equation is an algebraic equation of the second degree in x.. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.
<h3>
According to the given information:</h3>
Total area = 7 square feet
and,
Total area = Length x Width
So,
7 = (2x + 3)(2x + 2)
7 = 4x2 + 4x + 6x + 6
7 = 4x2 + 10x + 6
4x2 + 10x + 6 - 7 = 0
4x2 + 10x - 1 = 0
Hence,
The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.
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I understand that the question you are looking for is:
Mary wants to hang a mirror in her room. the mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and 3 feet long. Square with an inner frame with height of 2 ft on the left frame and width of 3 ft on the top. Arrow on the bottom frame with an x and an arrow on the right frame with an x. Which quadratic equation can be used to determine the thickness of the frame, x?
A. x² + 14x - 2 = 0
B. 2x² + 10x - 7 = 0
C. 3x² + 12x - 7 = 0
D. 4x² + 10x - 1 = 0
Yo vivo en Granada, una ciudad pequeña que tiene monumentos muy importantes como la Alhambra.
Answer:
Step-by-step explanation:
3(2x + 7) - 2 (x + 5)
need to distibute
5x+10-2x+3
combine like terms
3x+13
divide
x=4.3
Answer: 14
Step-by-step explanation:
Input Data :
Point 1 (
x
A
,
y
A
) = (-4, -8)
Point 2 (
x
B
,
y
B
) = (10, -8)
Objective :
Find the distance between two given points on a line?
Formula :
Distance between two points = √
(x
B
−
x
A
)
2
+
(
y
B
−
y
A
)
2
Solution :
Distance between two points = √
(
10
− −
4
)
2
+
(
−
8
− −
8
)
2
= √
14
^2
+
0
^2
= √
196
+
0
= √
196
= 14
Distance between points (-4, -8) and (10, -8) is 14
It's the first one, an algebraic expression contains variables
