<u><em>Answer:</em></u>
AC = 10sin(40°)
<u><em>Explanation:</em></u>
The diagram representing the question is shown in the attached image
Since the given triangle is a right-angled triangle, we can apply the special trig functions
<u>These functions are as follows:</u>
sin(θ) = opposite / hypotenuse
cos(θ) = adjacent / hypotenuse
tan(θ) = opposite / adjacent
<u>Now, in the given diagram:</u>
θ = 40°
AC is the side opposite to θ
AB = 10 in is the hypotenuse
<u>Based on these givens</u>, we will use the sin(θ) function
<u>Therefore:</u>

Answer:
≈ 20.8 ft
Step-by-step explanation:
A right triangle is formed between the wall, the ground and the ladder.
The ladder is the hypotenuse , the wall and ground are the legs.
let h be the height of the wall, then using Pythagoras' identity
h² + 33² = 39²
h² + 1089 = 1521 ( subtract 1089 from both sides )
h² = 432 ( take the square root of both sides )
h =
≈ 20.8 ft ( to the nearest tenth )
Answer:
Triangle: True
Parallelogram: False, area is 63cm^2
Trapezoid: True
Step-by-step explanation:
Use area calculators on the internet to find the area of shapes.
1-8 is simple. Just subtract 8 from 1. so 1-8 = -7
Answer:
See proof below
Step-by-step explanation:
Two triangles are said to be congruent if one of the 4 following rules is valid
- The three sides are equal
- The three angles are equal
- Two angles are the same and a corresponding side is the same
- Two sides are equal and the angle between the two sides is equal
Let's consider the two triangles ΔABC and ΔAED.
ΔABC sides are AB, BC and AC
ΔAED sides are AD, AE and ED
We have AE = AC and EB = CD
So AE + EB = AC + CD
But AE + EB = AB and AC+CD = AD
We have
AB of ΔABC = AD of ΔAED
AC of ΔABC = AE of ΔAED
Thus two sides the these two triangles. In order to prove that the triangles are congruent by rule 4, we have to prove that the angle between the sides is also equal. We see that the common angle is ∡BAC = ∡EAC
So triangles ΔABC and ΔAED are congruent
That means all 3 sides of these triangles are equal as well as all the angles
Since BC is the third side of ΔABC and ED the third side of ΔAED, it follows that
BC = ED Proved