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3 years ago

If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain of (F g)(x)

Mathematics

2 answers:

laila [671]3 years ago

7 0

I think this attachment will help you

denis-greek [22]3 years ago

5 0

Answer:

domain will be ( -∞, ∞)

Step-by-step explanation:

The given functions are f(x) = x² - 1 and g(x) = 2x - 3

We have to find domain of (fog)(x)

We will find the function (fg)(x) first.

(fog)(x) = f[g(x)]

= (2x - 3)²

= 4x² + 9 - 12x - 1

= 4x² - 12x + 8

= 4 (x² - 3x + 2)

The given function is defined for all values of x.

Therefore, domain will be ( -∞, ∞)

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pav-90 [236]

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3 years ago

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sergij07 [2.7K]

The answer is B., valid because people were chosen randomly
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3 years ago

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Find the measure of the reference angle for an angle of 152º.

AlladinOne [14]

Answer:

28 deg

Step-by-step explanation:

Reference angle is the smallest angle formed by the terminal ray, x-axis, and origin. So at 180 you are on the x-axis so just for this question you have to do 180-152=28.

The reference angle should be a positive between 0 and 90 degrees.

7 0

3 years ago

Use the table to identify the values of p and q that should be used to factor2 +3x-10 as (x+ p)(x q).

Nat2105 [25]

we are given

$x^2 +3x -10$

it's factor as (x+p)(x+q)

so, we can write as

$x^2 +3x -10= (x+p)(x+q)$

we can simplify it

$x^2 +3x -10= x^2 +(p+q)x +pq$

now, we can compare both sides

coefficient of x must be equal

so, we get

$3= (p+q)$

$(p+q)=3$

now, we can look at the table where p+q =3

so, we can see that when p+q=3 .... then p=-2 and q=5

so, option-A.......Answer

3 0

4 years ago

Write down the coordinates of the image of the point (2-3) under reflecting about the line joining the points (3, 5) and (3,7)

Murrr4er [49]

Answer:

(4 , -3)

Step-by-step explanation:

the points (3 , 5) and (3 , 7) have the same x-coordinates 3

then ,the line D joining them has the equation

D : x = 3

the image of the point A(2 , -3) under reflecting about The line D ,

lie on the line ∆ perpendicular to D and passes through A.

∆ perpendicular to D then the equation of ∆ is :

∆ : y = a ,where a is a real number.

Calculating ‘a’ :

∆ passes through A

Then

-3 = a

Therefore

the final equation of ∆ is :

∆ : y = -3

Obviously, the lines D and ∆ intersect at the point M(3 , -3)

FINAL STEP :

<u><em>Calculating the coordinates of the point B(x , y) image of the point A(2 , -3) </em></u>

M is the midpoint of the line segment AB :

Then

3 = (2 + x)/2 and -3 = (-3 + y)/2

Then

x = 4 and y = -3.

4 0

2 years ago