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4 years ago

You are starting with 2 pounds of 30% acetic acid solution. You want to dilute

Chemistry

1 answer:

Tpy6a [65]4 years ago

8 0

Answer:

The mass of water to be added is 2 pounds

Explanation:

The given parameters are;

The mass of the given solution = 2 pounds

The concentration of the given solution = 30%

The desired concentration of the solution = 15%

The mass, m of the acetic acid in the given solution = 30% × 2 pounds

m = 30/100 × 2 pounds = 0.6 pounds

To make a 15% acetic acid solution of acetic acid, the mass X of the required volume, is given as follows;

15% of X = 0.6 pounds

15/100 × X = 3/20 × 0.6 pounds

∴ The mass of the solution required X = 0.6 × 20/3 = 4 pounds

The mass of the solution that will contain 0.6 pounds of acetic acid giving a 15% acetic acid solution is 4 pounds

Therefore, the mass of water to be added to the original solution to make the a 15% acetic acid solution is 2 pounds.

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Use the information in the table about four different electric circuits to answer the question

ycow [4]

Answer:

Circuit 4

Explanation:

To know the correct answer to the question given above, we shall determine the current in each circuit. This can be obtained as follow:

For circuit 1:

Resistance (R) = 0.5 ohms

Voltage (V) = 20 V

Current (I) =?

V = IR

20 = I × 0.5

Divide both side by 0.5

I = 20 / 0.5

I = 40 A

For circuit 2:

Resistance (R) = 0.5 ohms

Voltage (V) = 40 V

Current (I) =?

V = IR

40 = I × 0.5

Divide both side by 0.5

I = 40 / 0.5

I = 80 A

For circuit 3:

Resistance (R) = 0.25 ohms

Voltage (V) = 40 V

Current (I) =?

V = IR

40 = I × 0.25

Divide both side by 0.25

I = 40 / 0.25

I = 160 A

For circuit 4:

Resistance (R) = 0.25 ohms

Voltage (V) = 60 V

Current (I) =?

V = IR

60 = I × 0.25

Divide both side by 0.25

I = 60 / 0.25

I = 240 A

SUMMARY

Circuit >>>>>> Current

1 >>>>>>>>>>> 40 A

2 >>>>>>>>>>> 80 A

3 >>>>>>>>>>> 160 A

4 >>>>>>>>>>> 240 A

From the above calculation, circuit 4 has the greatest electric current.

8 0

3 years ago

What are the formal charges of both chlorines and iodine in icl2?

sergejj [24]

Answer:

Explanation:

Formal charge of ICl₂⁻

Formal charge = group no - ( no of non bonding electrons +no of bonds)

In I there are 7 electrons in outermost orbit . If we add one more electrons due to - ve charge on the ion , it becomes eight . This centrally placed iodine forms two single bond with two chlorine atoms on either side.

Each of chlorine atoms also contains 7 valance electrons like iodine.

So formal charge of chlorine

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 6 + 1 )

= 0

So formal charge of iodine

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 5 + 2 )

Formal charge of ICl₂⁺

In this case , central iodine will have only 6 valence electrons due to absence one electron.

So formal charge of chlorine in ICl₂⁺

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 6 + 1 )

= 0

formal charge of iodine in in ICl₂⁺

7 - ( 4 + 2)

= 1

6 0

4 years ago

Give the electron configuration of vanadium (V), atomic number 23

saveliy_v [14]

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³ or [Ar] 4s²3d³

<h3>Further explanation</h3>

Given

Vanadium, atomic number 23

Required

The electron configuration

Solution

In an atom, there are levels of energy in the shell and subshell

This energy level is expressed in the form of electron configurations.

Charging electrons in the subshell uses the following sequence:

The electron configuration is based on the atomic number which indicates the number of electrons of the atom

Vanadium has the atomic number 23, so the number of electrons = 23

Electron configuration:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³

or we can write it using the noble gas notation

[Ar] 4s²3d³

4 0

3 years ago

Explain how a seismometer works

Radda [10]

<span>will record an earthquake by a plotting vibrations versus time.
can determine the time of arrival of the first P-wave and the time of arrival of the first S-wave.</span>

4 0

3 years ago

Read 2 more answers

Write and balance the combination reaction for the heating of solid magnesium in the presence of nitrogen gas. In a particular e

Makovka662 [10]

Answer:

The mass of magnesium that has been consumed, was 6.69 g

Explanation:

The reaction is this one:

3Mg (s) + N₂(g) → Mg₃N₂

3 moles of solid magnesium react with 1 mol of nitrogen, to make 1 mol of magnesium nitride.

If 9.27 grams of nitrogen react, we see that ratio is 1:1, so we make 9.27 grams of nitride.

Mass / Molar mass = Moles

9.27 g / 100.9 g/m = 0.092 moles

If we have 0.092 moles of nitride, ratio between Mg is 1:3 so, the rule of three will be:

1 mol of Nitride was produced by 3 moles of Mg (s)

0.092 moles of nitride were produced by, (0.092 .3)/1 = 0.275 moles

Mass og Mg = 24.3 g/m

Molar mass . Moles = Mass

0.275 m . 24.3g/m = 6.69 g

4 0

3 years ago