Answer:
The play will be more appealing to a younger audience.
Explanation:
A younger audience will more likely appreciate current pop hits rather than classical score.
Answer:
An inverse relationship can neither be represented by a straight line nor by a bar chart. But it can be represented by "xy = k"
Explanation:
Inverse relation is used for the values which are inversely related to each other. For example: Let suppose you have a value x and y. Then an increase in the value of x will result in the decrease of value y. Mathematically it is represented as,
x ∝ 1 / y
Where;
∝ = proportionality
Replacing the proportionality sign by a constant value "k" the relation becomes,
x = k / y
Solving for k,
x y = k
Conclusion:
Hence, an inverse relationship can be represented by "xy = k"
Answer: 39.948 grams
Explanation:
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Ar, or 39.948 grams
Answer: Option (b) is the correct answer.
Explanation:
The process in which sediment moves downhill is known as mass movement.
Different types of mass movement are landslides, mud slides, slump, creep etc.
Mud flow contains mass of saturated rock particles of all sizes. Mud flow arises due to sudden flood of water or due to heavy rain in a dry region (semi-arid region). Soil and rocks from a large slope area flow along with the flood water and gets washed to a gulch or canyon.
As a result, debris and water moves down canyon and lay out on the gentle slopes below.
Thus, we can conclude that mud flow is most likely facilitates mass movement after heavy rains in a dry region.
<span>a. Use PV = nRT and solve for n = number of mols O2.
mols NO = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR.
b.
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L.
</span>and % will be 60%.
