To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
It is Constant. The cost per pound is 2.50 dollars. two would be on the x-axis, and 5 dollars would be on the y-axis. likewise, 3 would be on the x-axis, and 7.50 dollars is on the y-axis. 5 pounds would cost : $12.50
The rays shown in the pictur: Ray VX, YZ , XY, ZV..... Plus more!
Expand the square: 4(x-11)^ =25
4(x-11)(x-11)=25
Distribute : 4(x-11)(x-11)=25
4(x(x-11)-11(x-11))=25
Distribute: 4(x(x-11)-11(x-11))=25
4(x^-11x-11(x-11))=25
Solution: x=17/2
x=27/2
hope that helps
Answer:
-4 (5v -3v -6) -9v (use the distributive property)
-20v +12v +24 -9v (combine all like terms)
-17v +24
