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3 years ago

Geometry help.. Image included, Thanks!

Mathematics

1 answer:

Gnoma [55]3 years ago

8 0

Area of a parallelogram = base * height

base = 5 in

height = 5 in

Area of the parallelogram = 5*5 = 25 in²

Answer is B. 25 units².

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Please help me its a math problem thank you i give brainlist

inna [77]

Answer:

1.875

Step-by-step explanation:

the average rate of change of g(x) in the closed interval [ a, b ] is

$\frac{g(b)-g(a)}{b-a}$

here [a, b ] = [- 1, 3 ] , then

g(b) = g(3) = 2³ + 1 = 8 + 1 = 9

g(a) = g(- 1) = $2^{-1}$ + 1 = $\frac{1}{2}$ + 1 = 1.5

then

average rate of change = $\frac{9-1.5}{3-(-1)}$ = $\frac{7.5}{4}$ = 1.875

8 0

2 years ago

Read 2 more answers

Kevin is taking a two-part test in social studies

Phantasy [73]

Answer:

He need to earn 32 points on part 2.

5 0

3 years ago

the length of the rectangle is measured as 370mm correct to 2 significant figures.a) what is the upper bound for the length?the

ivanzaharov [21]

Answer:

a) 375

b) 7062.75 mm²

Step-by-step explanation:

b) We need to find the shortest possible width and length to get the smallest possible area.

To get the boundaries for 19.4, we go on to the next significant figure (the hundredths) and ± 5 of them.

The boundaries are, therefore: 19.35 - 19.45

As for the length, we can see they've added 5 units as the measurement is correct to 2 sig' figures, which is the tens.

And so, if we do as we did before, we go to the next sig' figure (the units) and ± 5 of them, we get the boundaries to be 365 - 375.

Now, we just multiply the lower bounds of the length and width to get the minimal/lower-bound area:

365 * 19.35 = 7062.75 mm²

7 0

2 years ago

If y is directly proportional to x and y = 17.5 when x=21 find y when x=39

morpeh [17]

direct proportion y=kx , k is constant and k does not equal to 0.

17.5=k(21)

k=5/6

when x =39

y=5/6 ×39

y=32.5

4 0

3 years ago

Read 2 more answers

In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta

Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.3246

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0

3 years ago