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3 years ago

How do you not know your asleep till your awake lol

Physics

2 answers:

ozzi3 years ago

6 0

Answer:

i think since our body is relaxed and our minds are relaxing. i'm not completely sure but i just think that we are kinda partially unconscious in a sense, but i don't really know. i'm not a professional or anything so i guess i don't have a lot of experience in these types of things lol.

Explanation:

anyways,

have a good day !

~mina-san

lidiya [134]3 years ago

6 0

Answer:

I don't know one minute I'm sleeping the next it's morning XD

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Absolute zero (K=0 or -273.15°C) is what temperature on the Farenheit scale? a) 459.4°F b) -301.43 °F c) 233.05°F d) -40.15°F e

ANEK [815]

Answer:

e) None of these is true

Explanation:

Given that

Temperature = 0 K

We know that relationship between kelvin and Farenheit scale

$\dfrac{K-273}{100}=\dfrac{F-32}{180}$

Now by putting the values

$\dfrac{K-273}{100}=\dfrac{F-32}{180}$

$\dfrac{0-273}{100}=\dfrac{F-32}{180}$

So F= - 459.67°F

So we can say that 0 K is equal to - 459.67°F.

So the our option e is correct.

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4 years ago

Our solar system is situated within the arm of the Milky Way galaxy. TRUE FALSE

Marizza181 [45]

Answer:

FALSE!!!!

Explanation:

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3 years ago

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At what temperature is Fahrenheit scale reading equal to twice of celsius?

gayaneshka [121]

At -24.613 F temperature is the Fahrenheit scale reading equal to twice that of the Celsius and at 160 F temperatuar is the Fahrenheit scale reading equal to half that of the Celsius? So, 160 degrees Celsius will equal 320 degrees Fahrenheit.

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3 years ago

A throttle position sensor waveform is going to be observed. At what setting should the volts per division be set to see the ent

Mars2501 [29]

Answer:

1 V / div

Explanation:

Solution:

- The vertical scale has eight divisions.

- If each division is set to equal 1 volt, the display will show 0 to 8 volts.

- This is okay in a 0 to 5 volt variable sensor such as a throttle position (TP) sensor.

- The volts per division (V/div) should be set so that the entire anticipated waveform can be viewed.

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3 years ago

You build a solenoid containing 500 windings over a 0.20-m length, with a loop radius of 0.025 m for each winding. the current i

marta [7]

The inductance of a solenoid is given by:
$L= \frac{\mu_0 N^2 A}{l}$
where
$\mu_0$ is the vacuum permeability
N is the number of turns of the solenoid
A is the area of one loop of the solenoid
l is its length

For the solenoid in our problem, N=500, and the radius of one loop is r=0.025 m, so the area of one loop is
$A=\pi r^2 = \pi (0.025 m)^2 = 1.96 \cdot 10^{-3} m^2$
and its length is l=0.20 m

So the inductance of the solenoid is
$L= \frac{(4 \pi \cdot 10^{-7} NA^{-2})(500)^2(1.96 \cdot 10^{-3} m^2)}{ 0.20 m}=3.08 \cdot 10^{-3} H$

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4 years ago