John can run with the velocity of 5 m/s
Explanation:
- Kinetic energy is defined as the energy is being used to do an activity, basically energy associated with the motion of objects in the universe.
- The formula used to find the kinetic energy of an object is k =
where as k represented as kinetic energy, m is the mass of the object and v is the velocity of the given object.
- Here, to find the answer we have to re-write the equation as
![v = \sqrt[2]{\frac{2 k}{m} }](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B2%20k%7D%7Bm%7D%20%7D)
- Given, the mass of the object, here it is John = 80 kg, energy needs to be converted to kinetic energy, k = 1000 J.
- Hence, substitute all the values, then you would velocity as 5 m/s
This is most likely an example of kinetic energy.
Answer:
the tension in the part of the cord attached to the textbook is 7.4989 N
Explanation:
Given the data in the question;
As illustrated in the image below;
first we determine the value of the acceleration,
along vertical direction; we use the second equation of motion;
y = ut +
a
t²
we substitute;
0 m/s for u, 1.29 m for y, 0.850 s for t,
1.29 = 0×0.850 +
×a
×(0.850)²
1.29 = 0.36125a
a
= 1.29 / 0.36125
a
= 3.5709 m/s²
Now when the text book is moving with acceleration , the dynamic equation will be;
T₁ = m₁a
where m₁ is the mass of the text book ( 2.10 kg )
a
is the vertical acceleration ( 3.5709 m/s² )
so we substitute
T₁ = 2.10 × 3.5709
T₁ = 7.4989 N
Therefore, the tension in the part of the cord attached to the textbook is 7.4989 N
Explanation:
this is the answer.....................
.