Answer:
The wavelength of the radiation absorbed by ozone is 319.83 nm
Explanation:
Given;
frequency of absorbed ultraviolet (UV) radiation, f = 9.38×10¹⁴ Hz
speed of the absorbed ultraviolet (UV) radiation, equals speed of light, v = 3 x 10⁸ m/s
wavelength of the absorbed ultraviolet (UV) radiation, λ = ?
Apply wave equation for speed, frequency and wavelength;
v = fλ
λ = v / f
λ = (3 x 10⁸) / (9.38×10¹⁴)
λ = 3.1983 x 10⁻⁷ m
λ = 319.83 x 10⁻⁹ m
λ = 319.83 nm
Therefore, the wavelength of the radiation absorbed by ozone is 319.83 nm
<span>The time needed for a wave to make one complete cycle is its period.</span>
The thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.
<h3>What is wage speed?</h3>
It should be noted that wave speed simply means the distance that a wave travels during a particular time.
It should be noted that higher tension leads to an increase in the speed of the wave.
Therefore, the thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.
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Answer:
The maximum height reached by the ball is 16.35 m.
Explanation:
Given;
initial velocity of the ball, u = 17.9 m/s
the final velocity of the ball at the maximum height, v = 0
The maximum height reached by the ball is given by;
v² = u² + 2gh
During upward motion, gravity is negative
v² = u² + 2(-g)h
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u² / 2g
h = (17.9)² / (2 x 9.8)
h = 16.35 m
Ttherefore, the maximum height reached by the ball is 16.35 m.
Answer:
20 m/s
30 m/s
Explanation:
Given:
v₀ = -10 m/s
a = -9.8 m/s²
When t = 1 s:
v = v₀ + at
v = (-10 m/s) + (-9.8 m/s²) (1 s)
v = -19.8 m/s
When t = 2 s:
v = v₀ + at
v = (-10 m/s) + (-9.8 m/s²) (2 s)
v = -29.6 m/s
Rounded to one significant figures, the speed of the ball at 1 s and 2 s is 20 m/s and 30 m/s, respectively.