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mash [69]
3 years ago
14

How does most of the water in the water cycle move from lakes and rivers directly back into the atmosphere?

Chemistry
2 answers:
olga2289 [7]3 years ago
8 0
It happens through precipitation when water evaporates from the suns rays and rises into the atmosphere
AnnyKZ [126]3 years ago
7 0
It goes from lakes and as the temp rises, it evaporates into clouds. from there, the clouds get heavy, and it produces rain, and the rain forms rivers and then back into lakes.
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What is the difference between a strong base and a weak base?
slamgirl [31]

Answer:

A strong base produces more ions in solution than a weak base.

Explanation:

3 0
3 years ago
Can someone please help me with this question? I don't understand it
mr Goodwill [35]
There  are 3 different elements
8 0
3 years ago
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The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

7 0
3 years ago
Which of the following is not part of our solar system?
andreyandreev [35.5K]

Answer:

none of the above

Explanation:

4 0
2 years ago
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Change 23 degrees Celsius to F
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Rewrite the formula C=5/9(F-32) substituting 23 for C: 23=5/9(F-32), then multiply both sides by the reciprocal of 5/9.
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41.4=F-32; add 32 to both sides.
41.4+32=F-32+32
73.4=F
8 0
3 years ago
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