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777dan777 [17]
3 years ago
5

Simplify 3(tan^2 theta - sec^2 theta) a. 1 b. 0 c. -3 d. 3 *ITS NOT D*

Mathematics
1 answer:
nlexa [21]3 years ago
4 0

Answer:

it's option c. - 3

Hope it will help :)❤

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What is tha greatest commmon factor off 40/60​
Gala2k [10]

\frac{40}{2}  \:  \frac{60}{2}

divide it by 2 if its ok to divide if not no need to divide if there not combine to similar terms

3 0
3 years ago
Solve for x 26=3x+2x-9
umka2103 [35]
Combine like terms on the right side:

3x + 2x = 5x
26 = 5x - 9

Add 9 to both sides:

35 = 5x

Divide both sides by 5 to get x by itself:

x = 7

The value of x is 7.


8 0
4 years ago
Most plumbing companies charge a fee to come to your house plus a charge per hour of work. The fees and charges for two plumbing
lord [1]

Answer:

Company A: y=40x+50

Company B: y=50x+25

Step-by-step explanation:

The initial fee is the y-intercept, as that is the cost at x = 0, or the cost before any time has passed. Afterwards, the rate the cost increases is the slope.

Linear equation in slope-intercept form:

y=mx+b

where m is the slope and b is the y-intercept.

Company A charges $50 up front and $40 per hour afterwards, so the equation would be:

y=40x+50

Company B charges $25 up front and $50 per hour, so:

y=50x+25

7 0
3 years ago
What is the percent decrease from 376 to 0.
Alekssandra [29.7K]

hey its -100 percent. the negative to show decrease.

6 0
3 years ago
Read 2 more answers
In the children’s game Don’t Break the Ice, small plastic ice cubes are squeezed into a square frame. Each child takes a turn ta
guajiro [1.7K]

Answer:

(29.46 mm, 29.54 mm).

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 43 - 1 = 42

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 42 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.018

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.018\frac{0.12}{\sqrt{43}} = 0.04

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 29.5 mm - 0.04mm = 29.46 mm

The upper end of the interval is the sample mean added to M. So it is 29.5 mm + 0.04mm = 29.54 mm

The 95% confidence level for the true mean width is: (29.46 mm, 29.54 mm).

5 0
3 years ago
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