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777dan777 [17]
3 years ago
5

Simplify 3(tan^2 theta - sec^2 theta) a. 1 b. 0 c. -3 d. 3 *ITS NOT D*

Mathematics
1 answer:
nlexa [21]3 years ago
4 0

Answer:

it's option c. - 3

Hope it will help :)❤

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If electricity power failures occur according to a Poisson distribution with an average of 3 failures every twenty weeks, calcul
Wittaler [7]

Answer:

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

3 failures every twenty weeks

This means that for 1 week, \mu = \frac{3}{20} = 0.15

Calculate the probability that there will not be more than one failure during a particular week.

Probability of at most one failure, so:

P(X \leq 1) = P(X = 0) + P(X = 1)

Then

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.15}*0.15^{0}}{(0)!} = 0.8607

P(X = 1) = \frac{e^{-0.15}*0.15^{1}}{(1)!} = 0.1291

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.8607 + 0.1291 = 0.9898

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

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3 years ago
What transformation was used to create this section of the picture? o dilation O reflection O translation​
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Please help i will give brainliest but answer all!!
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Answer:

19. reflection (-1, -3)

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