Answer:Hummingbirds have long, needlelike beaks they use to probe deep into flowers. The hummingbird's beak is just a protective sheath for its tongue, which is actually what the hummingbird is using to get the nectar out of the flower. The tip of their tongue is forked and has little hairs all over it.
Explanation:
Answer:
2 moles of SO₂
Explanation:
Equation of reaction
H₂S + 3H₂SO₄ → 4H₂O + 4SO₂
From the equation of reaction above,
1 mole of H₂S will produce 4 moles of SO₂
1 mole of H₂S = 4 moles of SO₂
0.5moles of H₂S = zmoles of SO₂
z = (0.5*4) / 1
z = 2 moles of SO₂
0.5 moles of H₂S will produce 2 moles of SO₂
Answer:
is the value of the equilibrium constant for this reaction at 756 K.
Explanation:
Equilibrium concentration of 
![[COCl_2]=7.40\times 10^{-4} M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D7.40%5Ctimes%2010%5E%7B-4%7D%20M)
Equilibrium concentration of 
![[CO]=3.76\times 10^{-2} M](https://tex.z-dn.net/?f=%5BCO%5D%3D3.76%5Ctimes%2010%5E%7B-2%7D%20M)
Equilibrium concentration of 
![[Cl_2]=1.78\times 10^{-4} M](https://tex.z-dn.net/?f=%5BCl_2%5D%3D1.78%5Ctimes%2010%5E%7B-4%7D%20M)
The expression of an equilibrium constant can be written as;
![K_c=\frac{[CO][Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
is the value of the equilibrium constant for this reaction at 756 K.
Both HF and HBr experience H-bond, dipole, and dispersion forces. These forces allow the compounds to have stronger bonds with each other. HF would experience a higher amount of attraction between its molecules. This is because fluorine is more electronegative than bromine.
Hope this helps!
Answer:
oxidation occurs at the cathode.
Explanation:
In a voltaic cell electrons move from anode to cathode. At the anode, species give up electrons. This is an oxidation reaction depicted by the oxidation half equation. At the cathode, species accept electrons and become reduced. This is depicted by the reduction half equation. In summary; in a Voltaic cell, oxidation occurs at the anode while reduction occurs at the cathode.
