Hello, and thank you for posting your question here on brainly.
When you solve the equation x = y^2 + 1, you get this line.
(photo)
The line graphed takes both quadrants
I & IV, or 1 & 4.
Hope this helps! ☺♥
<h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
In this question, we're solving the equation with the absolute value.
In this case, we would be solving for x.
The equation we are solving is:
Lets solve:
Your answer would be x = 3 or x = -15
<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
Answer:
x=2, y=2
Step-by-step explanation:
3x + y = 8
2x + 4y = 12
Multiply the first equation by -4
-12x -4y = -32
Then add to the second equation
-12x -4y = -32
2x + 4y = 12
------------------------
-10x + 0y = -20
-10x = -20
Divide by -10
-10x/-10 = -20/-10
x =2
Now find y
3x+y = 8
3(2)+y = 8
6+y = 8
y = 8-6
y =2
F(-4) = 3 x 2 - 5(-4) + 4
3x2= 6
-5(-4)= 20
6-20= -14
-14+4= -10
f(-4) = -10
To solve this problem we will use the pythagorean theorem a^2+b^2=c^2
all we have to do is add 12^2+35^2=45^2
