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Ivan
3 years ago
12

You are traveling on a plane trip from Washington, D.C. to Cleveland, Ohio and the plane uses 1,260 MJ/passenger trip. If you ma

de the trip by car it would take 18 gallons/passenger trip. There are 142 MJ in a gallon of kerosene, a type of jet fuel. How many gallons of kerosene does it take to make the trip by plane?
Physics
1 answer:
forsale [732]3 years ago
3 0

Answer:

8.87 gallons of kerosene

Explanation:

Step 1: Given and required data

  • Energy to travel by plane per passenger trip: 1,260 MJ/passenger trip
  • Energy per gallon of kerosene: 142 MJ/gal

Step 2: Calculate how many gallons of kerosene it takes to make the trip by plane

We can calculate the amount of kerosene required by combining the factor provided in Step 1.

1 gal/142 MJ × 1,260 MJ/passenger trip = 8.87 gal/passenger trip

8.87 gallons of kerosene are required to make the trip by plane.

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A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s. How lo
Arlecino [84]

Answer:

t = 4.08 s

R = 40.8 m

Explanation:

The question is asking us to solve for the time of flight and the range of the rock.

Let's start by finding the total time it takes for the rock to land on the ground. We can use this constant acceleration kinematic equation to solve for the displacement in the y-direction:

  • Δx = v_0 t + 1/2at²

We have these known variables:

  • (v_0)_y = 0 m/s
  • a_y = -9.8 m/s²
  • Δx_y = -20 m

And we are trying to solve for t (time). Therefore, we can plug these values into the equation and solve for t.

  • -20 = 0t + 1/2(-9.8)t²
  • -20 = 1/2(-9.8)t²
  • -20 = -4.9t²
  • t = 4.08 sec

The time it takes for the rock to reach the ground is 4.08 seconds.

Now we can use this time in order to solve for the displacement in the x-direction. We will be using the same equation, but this time it will be in terms of the x-direction.

List out known variables:

  • v_0 = 10 m/s
  • t = 4.08 s
  • a_x = 0 m/s

We are trying to solve for:

  • Δx_x = ?

By using the same equation, we can plug these known values into it and solve for Δx.

  • Δx = 10 * 4.08 + 1/2(0)(4.08)²
  • Δx = 10 * 4.08
  • Δx = 40.8 m

The rock lands 40.8 m from the base of the cliff.

7 0
2 years ago
Need help on these 2 questions please????? Hurry
fredd [130]

Answer:

Question 1 the anwser is 300 meters.  Question 2 the answer is speed.

is Explanation:

3 0
3 years ago
What is the purpose of an experiment design?
Eddi Din [679]
An experimental design is used to assign variables for testing. In contrast to a control design where nothing is changed, the experimental design allows you to test various new inputs to see how they would vary from the original results.
5 0
3 years ago
The moon orbits the earth once every 27 days at a distance of 384400 km. The international space station orbits the earth at an
Leno4ka [110]

Answer:

ive never done this befor but i think its 36 times aroud earth a day

Explanation:

384400/400=961  

961% of 27 days is 40minuets

1440/40=36

7 0
2 years ago
A box is placed on a conveyor belt that moves with a constant speed of 1.05 m/s. The coefficient of kinetic friction between the
sveticcg [70]

Answer:

The box stops in 0.139 seconds, after moving 7.29cm (0.0729m) backwards relative to the belt.

Explanation:

As the box is initially at rest relative to the earth, it is moving backwards with a speed of 1.05m/s relative to the belt. Then, the frictional force acts on the box to make it stop relative to the belt. So, we first have to write the equations of motion of the box in each axis:

x: f_k=ma\implies a=\frac{f_k}{m} \\\\y: N-mg=0\implies N=mg

Since the frictional force f_k is equal to f_k=\mu_k N=\mu_k mg, then we have that the acceleration is:

a=\frac{\mu_k mg}{m}=\mu_k g

Now, from the definition of acceleration we get:

a=\frac{v-v_0}{t}\implies t=\frac{v-v_0}{a}

And, as the final velocity is zero because the box gets to a stop, we have:

t=-\frac{v_0}{a}=-\frac{v_0}{\mu_k g}

(Don't worry about the negative sign. It will disappear because the initial velocity is also negative, since we take the box initially moving backwards)

Then, plugging in the given values, we calculate the time:

t=-\frac{(-1.05m/s)}{0.770(9.81m/s^{2})}=0.139s

In words, the time the box takes to stop sliding relative to the belt is 0.139s.

The displacement of the box in this time, is given by the kinematics formula:

v^{2}=v_0^{2}+2ax\implies x=-\frac{v_0^{2}}{2\mu_kg}

Finally, we calculate the displacement:

x=-\frac{(1.05m/s)^{2} }{2(0.770)(9.81m/s^2)}=-0.0729m=-7.29cm

This means that the box moves 7.29cm backwards relative to the belt.

4 0
2 years ago
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