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vova2212 [387]
2 years ago
12

A student wants to determine the effect of mass on kinetic energy. She will drop two balls of the same size into a pool of water

. Which investigation method should the student use?(1 point) She should drop two balls with different masses from the same height. She should drop two balls with different masses from different heights. She should drop two balls of the same mass from the same height. She should drop two balls of the same mass from different heights.
Physics
1 answer:
Anastasy [175]2 years ago
4 0

Answer:

She should drop two balls with different masses from the same height

Explanation:

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Density of water is 1000 kg/m^3. What will be the volume of 35000 kg water?
d1i1m1o1n [39]
Volume = mass/density
Volume = 35000/1000
Volume = 35m^3
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Which of Newton's motion laws BEST explains WHY a rock falls when it is dropped from a bridge?
erma4kov [3.2K]
It’s A because it stays in motion whenever you drop it
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A water balloon is thrown horizontally from a tower that is 45 m high. It strikes the shoes of an unsuspecting passerby who is 4
LekaFEV [45]

Answer:

14.85 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) of tower = 45 m

Horizontal distance (s) moved by the balloon = 45 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the balloon to hit the shoe of the passerby. This is illustrated below:

Height (h) of tower = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

45 = ½ × 9.8 × t²

45 = 4.8 × t²

Divide both side by 4.9

t² = 45/4.9

Take the square root of both side

t = √(45/4.9)

t = 3.03 s

Finally, we shall determine the magnitude of the horizontal velocity of the balloon as shown below:

Horizontal distance (s) moved by the balloon = 45 m

Time (t) = 3.03 s

Horizontal velocity (u) =?

s = ut

45 = u × 3.03

Divide both side by 3.03

u = 45/3.03

u = 14.85 m/s

Thus, the magnitude of the horizontal velocity of the balloon was 14.85 m/s

4 0
3 years ago
A net force of 24 N is acting on a 4.0-kg object. Find the acceleration in m/s2.
Inessa [10]

Hi there!

We can use Newton's Second Law:
\Sigma F = ma

ΣF = Net force (N)
m = mass (kg)
a = acceleration (m/s²)

We can rearrange the equation to solve for the acceleration.

a = \frac{\Sigma F}{m}\\\\a = \frac{24}{4} = \boxed{6 \frac{m}{s^2}}

6 0
2 years ago
. A person weighing 750 N gets on an elevator.
Kobotan [32]

 

F = 750 N  (Force)

d = 10 m  (displacement )

t = 25 s   (time)

L = ?   (Mechanical work )  =  (Energy)

P = ?   (Power)

Solve:

L = F × d = 750 × 10 = 7500 Joules

P = L / t = 7500 / 25 = 300 Watts

5 0
3 years ago
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