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Nesterboy [21]
3 years ago
8

Help me please thx so much have a good one

Mathematics
1 answer:
bazaltina [42]3 years ago
8 0
Picture is blurrry.

Hope it help
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Plzzzzzzzz! A suitcase lock has a code 4 symbols long. The symbols on the lock are a star, a square, a circle, a triangle, a lin
34kurt

Answer:

                \dfrac{1}{30}

Step-by-step explanation:

6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:

6•5•4•3 = 360

If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.

So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:

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The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

\dfrac{1\cdot1\cdot4\cdot3}{6\cdot5\cdot4\cdot3}=\dfrac{1\cdot1}{6\cdot5}=\dfrac{1}{30}

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3 years ago
Simplify: x^5. X-^5?
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Answer:

i believe the answer you are looking for is 1?

Step-by-step explanation:

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