The degree of hotness and coldness of th body is.......

Put each event in order of its occurrence, according to the big bang theory. please note that more accurate calculations of the

GalinKa [24]

I think the events are already chronologically arranged correctly. It always have to start with the simplest elements, the hydrogen and helium. In fact, these are the elements that compose the stars. The nuclear fusion of hydrogen atoms to helium is what gives the stars and the sun their energy. So, this is followed by letter b, which is the formation of stars. Then, when these stars explode a stated in c, they produce even heavier elements. As a result, this big bang theory tells us that the universe is expanding because of this 'explosion'. In the end, it led to the formation of the sun, the planets and the universe. <em>Thus, the arrangement is: a, b, c and d.</em>

6 0

3 years ago

A (hypothetical) large slingshot is stretched 4.00 m to launch a 440 g projectile with speed sufficient to escape from Earth (11

RSB [31]

Answer:

(A) 3,449,600 N/m

(B) 62,720 poeple

Explanation:

extension of the sling shot (e) = 4 m

mass of projectile (m) = 440 g = 0.44 kg

speed of projectile (v) = 11.2 km/s = 11,200 m/s

average force a person can exert = 220 N

spring constant (k) = ?

(A) When all the elastic potential energy is converted to kinetic energy

$o.5ke^{2} = 0.5 mv^{2}$

rearranging the above equation

spring constant (K) = $\frac{0.5mv^{2} }{0.5e^{2}}$

spring constant (K) = $\frac{0.5x0.44x11,200^{2} }{0.5x4^{2}}$

spring constant (K) = $\frac{27,596,800}{8}$

spring constant (K) = 3,449,600 N/m

(B) force required to stretch the slingshot (F) = ke = 3,449,600 x 4 = 13,798,400 N

number of people required = required force / average force per person = 13,798,400 / 220 =62,720 poeple

5 0

3 years ago

A mover pushes a 30 kg crate across a level florr with a force of 250 N, but the crate accelerates at a rate of only 5.83 m/s sq

arlik [135]

Force of friction=75 N

Explanation:

we use Newton's second law of motion

F- Ff= ma

F = applied force=250 N

Ff= force of friction

a= acceleration= 5.83 m/s²

m= mass=30 kg

250- Ff= 30 (5.83)

Ff=250-30(5.83)

Ff=250-175

Ff=75 N

7 0

3 years ago

Which statement describes how Earth compares to the moon? Earth has more inertia than the moon. The moon has more gravitational

Juliette [100K]

Answer

Earth has more inertia than the moon.

6 0

3 years ago

Read 2 more answers

An RC car is carrying a tiny slingshot with a spring constant of 85 N/m at 0.2 m off the ground at 5.6 m/s. The sling shot is pu

ololo11 [35]

Answer:

The velocity of the steel pellet relative to the ground when it leaves the sling shot is approximately 5.960 meters per second.

Explanation:

Let suppose that RC car-slingshot-steelpellet is a conservative system, that is, that non-conservative forces (i.e. friction, air viscosity) can be neglected. The velocity of the steel pellet can be found by means of the Principle of Energy Conservation and under the consideration that change in gravitational potential energy is negligible and that the RC car travels at constant velocity:

$\frac{1}{2}\cdot (m_{C}+m_{P})\cdot v_{o}^{2} + \frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m_{C}\cdot v_{o}^{2} + \frac{1}{2}\cdot m_{P}\cdot v^{2}$

$\frac{1}{2}\cdot m_{P}\cdot v_{o}^{2} + \frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m_{P}\cdot v^{2}$

$m_{P}\cdot v_{o}^{2} + k\cdot x^{2} = m_{P}\cdot v^{2}$

$v^{2} = v_{o}^{2} + \frac{k}{m_{P}}\cdot x^{2}$

$v = \sqrt{v_{o}^{2}+\frac{k}{m_{P}}\cdot x^{2} }$ (1)

Where:

$v_{o}$ - Initial velocity of the steel pellet, measured in meters per second.

$v$ - Final velocity of the steel pellet, measured in meters per second.

$k$ - Spring constant, measured in newtons per meter.

$m_{P}$ - Mass of the steel pellet, measured in kilograms.

$m_{C}$ - Mass of the RC car, measured in kilograms.

$x$ - Initial deformation of the spring, measured in meters.

If we know that $v_{o} = 5.6\,\frac{m}{s}$ , $k = 85\,\frac{N}{m}$ , $m_{P} = 0.025\,kg$ and $x = 0.035\,m$ , then the velocity of the steel pellet relative to the ground when it leaves the sling shot is:

$v = \sqrt{\left(5.6\,\frac{m}{s} \right)^{2}+\frac{\left(85\,\frac{N}{m} \right)\cdot (0.035\,m)^{2}}{0.025\,kg} }$

$v \approx 5.960\,\frac{m}{s}$

The velocity of the steel pellet relative to the ground when it leaves the sling shot is approximately 5.960 meters per second.

5 0

3 years ago

The degree of hotness and coldness of th body is.......​

The degree of hotness and coldness of th body is.......