Answer:
23.7402 m
21.582 m/s
310.521816 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
g = Acceleration due to gravity = 9.81 m/s² = a
Equation of motion
The drop distance is 23.7402 m
When they hit the air bags at the bottom of the tower the speed of the experiments is 21.582 m/s
The final speed of the fall will be the initial velocity of stopping
The average stopping acceleration is 310.521816 m/s²
Answer:
By using the formula
Z.t= average number of events
=10/100 ×1
=0.1hertz
Answer:
In nuclear power plants, energetic neutrons are directed into a sample of the isotope uranium-235. ... A common fission reaction produces barium-141 and krypton-92. In this particular reaction, one uranium nucleus breaks into a barium nucleus, a krypton nucleus, and two neutrons
metals share the properties of metals such as malleable, ductile and lustrous
... For most of every night, I exert a significant vertical force on my bed.
But my bed does not move.
... The same is true for the seat of my chair during dinner, and the ground under my feet when I stand or walk.
... When I am waiting for the bus, I almost always lean against the light pole,
exerting a considerable horizontal force against it. I have been doing this
for several years now, yet the light pole is still exactly where it has always stood.