Calcula x para que sean ciertas las igualdades siguientes:

Mathematics

1 answer:

ZanzabumX [31]3 years ago

8 0

A. 81
b. no entiendo la pregunta
c. 32
d. 64
e. 81
f. 1000

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How do i do this? i'm so lost. please explain and show your work

elena-s [515]

You want to make sure to factor each equation as much as you can first.
So just focus on the numerator first. $x^3-6x^2+8x$
To factor the numerator:
$(x)(x^2-6x+8)$ factor out an x
$(x)(x-4)(x-2)$ factor out the rest completely.

Now for the denominator: $-4x^2+4x+24$
$(-4)(x^2+x+6)$ factor out a -4
$(-4)(x+3)(x-2)$ factor out the rest.

This leaves you with:
$\frac{(x)(x-4)(x-2)}{(-4)(x+3)(x-2)}$

Then you can simplify:
$\frac{(x)(x-4)}{(-4)(x+3)}$

I'm not sure what you're supposed to find exactly, so if you need more help you can ask me (:

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4 years ago

10 POINTS so easy if you are ish smart WILL MRAK BRAINLEST SUPER EASY ISH NOT FOR ME THOUGH

IrinaK [193]

Answer:

Step-by-step explanation:

Both have the same surface area. The numbers are just rearranged.

Is the correct answer.

The surface area of the first one is 2*8*5 + 2*8*6 + 2*5*6 = 236

The surface area of the second is 2*10*8 + 2*10*3 + 2*8*3 = 244

Another rearrangement. Not the answer.

4 0