What is the equation of the line that passes through the point (8,-4) and has a slope of 3?
2 answers:
In order to solve it you insert the point in slope from
the equation is
Y=Mx+b
Plug it in as
-4=3(8)+b
-4=24+b
Then subtract 24
B=-28
So
The answer is
Y=3x-28
Y-y1=m(x-x1)
(8, -4) 8 is x1 and -4 is y1
so y- (-4) = 3 (x -8)
make 4 a positive then y + 4 = 3x - 24
subtract 4 from 24 then y=3x-20
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