What is the equation of the line that passes through the point (8,-4) and has a slope of 3?
2 answers:
In order to solve it you insert the point in slope from
the equation is
Y=Mx+b
Plug it in as
-4=3(8)+b
-4=24+b
Then subtract 24
B=-28
So
The answer is
Y=3x-28
Y-y1=m(x-x1)
(8, -4) 8 is x1 and -4 is y1
so y- (-4) = 3 (x -8)
make 4 a positive then y + 4 = 3x - 24
subtract 4 from 24 then y=3x-20
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Step-by-step explanation:
Answer:
P = 16x + 8
Step-by-step explanation:
Perimeter of a rectangle
= 2(L + W)
Given
L = 5x + 4 and
W = 3x
Therefore
Perimeter = 2(5x + 4 + 3x)
Rearrange the expression
P = 2(5x + 3x + 4)
P = 2(8x + 4)
Now expand the bracket
P = 2 x 8x + 2 x 4
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