Question

What is the equation of the line that passes through the point (8,-4) and has a slope of 3?

Answer 1

In order to solve it you insert the point in slope from

the equation is
Y=Mx+b

Plug it in as

-4=3(8)+b


-4=24+b

Then subtract 24

B=-28

So

The answer is

Y=3x-28

Answer 2

Y-y1=m(x-x1)

(8, -4) 8 is x1 and -4 is y1
so y- (-4) = 3 (x -8)
make 4 a positive then y + 4 = 3x - 24
subtract 4 from 24 then y=3x-20