What is the equation of the line that passes through the point (8,-4) and has a slope of 3?

2 answers:

8 0

In order to solve it you insert the point in slope from

the equation is
Y=Mx+b

Plug it in as

-4=3(8)+b

-4=24+b

Then subtract 24

B=-28

So

The answer is

Y=3x-28

sineoko [7]2 years ago

8 0

Y-y1=m(x-x1)

(8, -4) 8 is x1 and -4 is y1
so y- (-4) = 3 (x -8)
make 4 a positive then y + 4 = 3x - 24
subtract 4 from 24 then y=3x-20

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What is the rate of change of y=-4/9x+5

WARRIOR [948]

Answer:

Rate of change of y is $- \frac{4}{9}$

Step-by-step explanation:

$y = - \frac{4}{9} x + 5 \\ \\ differentiating \: with \: respect \: to \: x \\ \\ \frac{dy}{dx} = - \frac{4}{9} \frac{d}{dx} x + \frac{d}{dx} 5 \\ \\ \frac{dy}{dx} = - \frac{4}{9} .1 + 0 \\ \\ \huge \red{\frac{dy}{dx} = - \frac{4}{9} } \\ \\ rate \: of \: change \: of \: y =- \frac{4}{9}$