I am pretty sure the answer is C.
Answer:
The frictional force needed to overcome the cart is 4.83N
Explanation:
The frictional force can be obtained using the following formula:
![F= \mu R](https://tex.z-dn.net/?f=F%3D%20%5Cmu%20R)
where
is the coefficient of friction = 0.02
R = Normal reaction of the load =
=
= ![241.52N](https://tex.z-dn.net/?f=241.52N)
Now that we have the necessary parameters that we can place into the equation, we can now go ahead and make our substitutions, to get the value of F.
![F=0.02 \times 241.52N](https://tex.z-dn.net/?f=F%3D0.02%20%5Ctimes%20241.52N)
F = 4.83 N
Hence, the frictional force needed to overcome the cart is 4.83N
It confirmed medeleeve's hypothesis (prediction) and showed the use of his table
A.
because the nucleus contains protons and neutrons BUT neutrons are neutral and protons are positive, so the answer is A