To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:

$V = \frac{k_e q}{r}$

$k_e$ = Coulomb's constant

q = Charge

r = Radius

At the same time

$U = \frac{k_e q_1q_2}{r}$

The values of variables are the same, then if we replace in a single equation we have this expression,

$U = Vq$

If we replace the values, we have finally that the charge is,

$V = 800V$

$q = 1\mu C$

$U = (800V)(1*10^{-6}C)$

$U = 8*10^{-4}J$

Therefore the potential energy of the system is $8*10^{-4} J$

7 0

3 years ago

a student that just received their driver's license decides to buy a new car. he remembers from physics class that heat engines

blsea [12.9K]

Answer: the first law of thermodynamics

Explanation:

5 0

2 years ago

PLEASE HELP ME WITH THIS!!!!

vodka [1.7K]

Answer:

wasts materials such as cans. it can hit space crafts and satellites. no one has ever been killed by space debris, space vessels very rarely are seriously damaged.

7 0

2 years ago

If the amplitude of a wave is doubled, it has half the velocity. TRUE or FALSE?

blondinia [14]

Answer:

true

Explanation:

7 0

3 years ago