Calculate the 80th term of the following sequence 1 , 7 , 13 , 19
2 answers:
Answer:
a₈₀ = 475
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
7 - 1 = 13 - 7 = 19 - 13 = 6
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 1 and d = 6 , thus
a₈₀ = 1 + (79 × 6) = 1 + 474 = 475
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