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aleksley [76]
3 years ago
9

One way to ensure that the race ends up in a tie is to have the person who lost the original race run a shorter distance before

turning around. Instead of 80.0 m, what should that distance be
Physics
1 answer:
Vikki [24]3 years ago
6 0

Answer:

The appropriate answer is "72.8 m".

Explanation:

Let the distance be "x".

As per the question, we get

⇒ T_{Mia}=T_{Brandi}

or,

⇒ \frac{x}{13} +\frac{x}{7}=\frac{\80}{10} +\frac{80}{10}

By taking L.C.M, we get

⇒ \frac{20x}{91}=16

By applying cross-multiplication, we get

⇒ 20x=1440

⇒     x=\frac{1456}{20}

⇒        =72.8\ m

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A ball bearing took 20.9ˍs to fall when dropped from a helicopter. From what height was the ball bearing dropped?
mr_godi [17]

\boxed{ \bf{Given : }}

  • Time taken by a ball bearing = 20.9 seconds

  • Initial velocity,u = 0 m/s [ Body starts from rest ]

  • Acceleration due to gravity,g = 9.8 m/s²

\boxed{ \bf{To \:  be \:  calculated :  }}

From what height was the ball bearing dropped?

\boxed{ \bf{Solution : }}

By using second equation for freely falling body, we get:

\sf{h = ut +  \frac{1}{2} gt {}^{2} }

Substituting the values..

\sf\rightarrow \: h = 0 \times 20.9 +  \dfrac{1}{  \cancel{2}}  \times   \cancel{9.8} \times 20.9

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8 0
3 years ago
how large can the kinetic energy of an electron be that is localized within a distance (change in) x = .1 nmapproximately the di
elena-14-01-66 [18.8K]

Answer:

The kinetic energy of an electron is 1.54\times10^{-15}\ J

Explanation:

Given that,

Distance = 0.1 nm

We need to calculate the momentum

Using uncertainty principle

\Delta x\Delta p\geq\dfrac{h}{4\pi}

\Delta p\geq\dfrac{h}{\Delta x\times 4\pi}

Where, \Delta p = change in momentum

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Put the value into the formula

\Delta p=\dfrac{6.6\times10^{-34}}{4\pi\times10^{-10}}

\Delta p=5.3\times10^{-23}

We need to calculate the kinetic energy for an electron

K.E=\dfrac{p^2}{2m}

Where, P = momentum

m = mass of electron

Put the value into the formula

K.E=\dfrac{(5.3\times10^{-23})^2}{2\times9.1\times10^{-31}}

K.E=1.54\times10^{-15}\ J

Hence, The kinetic energy of an electron is 1.54\times10^{-15}\ J

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