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2 years ago

Regions around the nucleus where electrons are most likely to be found are called

Physics

2 answers:

IgorLugansk [536]2 years ago

4 0

Orbitals
Each orbital can have at most two electrons.
hope this helps x

ryzh [129]2 years ago

3 0

Answer:

orbitals

Explanation:

The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.

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Which best explains why the shape of a liquid can change?

topjm [15]

The particles in a liquid are extremely fast, not faster than a gas, but faster than a solid. The way the particles move allow you to get volume but not area for it doesn't have a defiant shape

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2 years ago

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You are looking down on a N = 9 turn coil in a magnetic field B = 0.5 T which points directly down into the screen. If the diame

Novay_Z [31]

Answer:

The magnitude of the voltage is $2.27\times10^{-4}\ V$ and the direction of the current is clockwise.

Explanation:

Given that,

Number of turns = 9

Magnetic field = 0.5 T

Diameter = 3 cm

Time t = 0.14 s

We need to calculate the flux

Using formula of flux

$\phi=NAB$

Put the value into the formula

$\phi=9\times\pi\times(1.5\times10^{-2})^2\times0.5$

$\phi=0.003180$

We need to calculate the emf

Using formula of emf

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{0.003180}{0.14}$

$\epsilon =-0.000227\ V$

$\epsilon=-2.27\times10^{-4}\ V$

Negative sign shows the direction of current.

Hence, The magnitude of the voltage is $2.27\times10^{-4}\ V$ and the direction of the current is clockwise.

8 0

3 years ago

a stone with a mass of 2.40 kg is moving with velocity (6.60î − 2.40ĵ) m/s. find the net work (in j) on the stone if its velocit

ch4aika [34]

By the work energy theorem, the total work done on the stone is given by its change in kinetic energy,

$W = \Delta K = \dfrac m2 ({v_2}^2 - {v_1}^2)$

We have

$\vec v_1 = (6.60\,\vec\imath - 2.40\,\vec\jmath)\dfrac{\rm m}{\rm s} \implies {v_1}^2 = \|\vec v_1\|^2 = 49.32 \dfrac{\rm m^2}{\rm s^2}$

$\vec v_2 = (8.00\,\vec\imath + 4.00\,\vec\jmath) \dfrac{\rm m}{\rm s} \implies {v_2}^2 = \|\vec v_2\|^2 = 80.0\dfrac{\mathrm m^2}{\mathrm s^2}$

Then the total work is

$W = \dfrac{2.40\,\rm kg}2 \left(80.0\dfrac{\rm m^2}{\rm s^2} - 49.32\dfrac{\rm m^2}{\rm s^2}\right) \approx \boxed{36.8\,\rm J}$

5 0

1 year ago

A bullet with a mass of 0.3 kg is fired out of a gun with a mass of 4 kg at 600 m/s. What is the recoil velocity on the gun?

slavikrds [6]

Answer:

According to the Conservation of Momentum,

Momentum of the gun = momentum of the bullet

M(gun)×V(gun)=m(bullet)×v(bullet)

4kg × V = 0.3kg × 600m/s²

V = (0.3 × 600)/4 = 45 m/s

The recoil velocity on the gun is <em><u>45 m/s</u></em>

<h3><u>45 m/s</u> is the right answer.</h3>

4 0

2 years ago

It is determined that a certain wave of infrared light has a wavelength of 8.45 mm. Given that c=2.99 ×108 m/s, what is the freq

irina [24]

Answer:

The frequency of infrared wave is 35.385 GHz

Explanation:

Given data:

Wavelength of infrared light = 8.45 mm = 8.45 x $10^{-3}$ m

Velocity of infrared light = 2.99 x $10^{8}$ m/s

To find: frequency of the infrared wave = ?

We know that the wavelength and frequency are inversely proportional and the formula to derive frequency with velocity and wavelength is:

c = μλ, where

c is velocity of light

μ is frequency of light

λ is wavelength of light

Hence the frequency of light μ = c/λ

= $\frac{2.99 x 10^{8} m/s }{8.45 x 10^{-3}m }$

= $\frac{299}{8.45}$ x $10^{9}$ $s^{-1}$

= 35.385 x $10^{9}$ Hz (since 1 $s^{-1}$ = 1 Hz)

= 35.385 GHz

6 0

3 years ago

Read 2 more answers