To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.
Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds
Horizontal distance
=0.335s*1.2m/s
=0.402 meters
Answer:

Explanation:
Hello.
In this case, since the force is defined in terms of the mass and acceleration by:

We can easily compute the mass by solving for it:

Whereas the force is 182 N (kg*m/s²) and the acceleration is 13 m/s², therefore, we obtain:

Best regards.
Answer:
-------1
Explanation:
beacuse that is what i know
Answer:
Their velocity is 0m/s because the first box was only 10 kg and the second box was double the weight