Answer:
Option B k > 0
Step-by-step explanation:
we know that
Observing the graph
The slope of the line is positive
The y-intercept is negative
we have
![3y-2x=k(5x-4)+6\\ \\3y=5kx-4k+6+2x\\ \\3y=[5k+2]x+(6-4k)\\ \\y=\frac{1}{3}[5k+2]x+(2-\frac{4}{3}k)](https://tex.z-dn.net/?f=3y-2x%3Dk%285x-4%29%2B6%5C%5C%20%5C%5C3y%3D5kx-4k%2B6%2B2x%5C%5C%20%5C%5C3y%3D%5B5k%2B2%5Dx%2B%286-4k%29%5C%5C%20%5C%5Cy%3D%5Cfrac%7B1%7D%7B3%7D%5B5k%2B2%5Dx%2B%282-%5Cfrac%7B4%7D%7B3%7Dk%29)
The slope of the line is equal to
![m=\frac{1}{3}[5k+2]](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B1%7D%7B3%7D%5B5k%2B2%5D)
Remember that the slope must be positive
so
The value of k is greater than -2/5
Analyze the y-intercept
1.5 is greater than zero
so
the solution for k is the interval ------> (1.5,∞)
therefore
must be true
k > 0
$142.60 for all three employees
To calculate the velocity, we use the given expression above which is <span>s(t) = −16t^2 + 144. First, we calculate the time it takes to reach the ground. Then, differentiate the expression and substitute time to the differentiated expression.
</span>s(t) = −16t^2 + 144
0 = -16t^2 + 144
t = 3
s'(t) = v = -32t
v = -32(3)
v = -96
Note: negative sign signifies that the object is going down
Answer:
A 3/5
Step-by-step explanation:Here’s one way to solve this problem.
Write sixty percent as a fraction having a denominator of one hundred.
Now, change sixty-hundredths to an equivalent fraction having a denominator of twenty, the total number of pitches.
Do this by dividing the numerator and the denominator by five.
Then, simplify the fraction twelve-twentieths by dividing the numerator and the denominator by four.
So, Lenora hit three-fifths of the pitches.
Depend on the time frame, A.M or P.M.
